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Dahasolnce [82]
3 years ago
14

How much heat must be removed from 15.5 g of water at 90.0°C to cool it to 43.2°C?

Chemistry
1 answer:
Katyanochek1 [597]3 years ago
3 0

Answer:

Heat, Q = 3035.073 J

Explanation:

It is given that,

Mass of water, m = 15.5 g

Initial temperature, T_i=90^{\circ} C

Final temperature, T_f=43.2^{\circ}

The specific heat of water is, c = 4.184 J/ g°C

The heat removed or absorbed by water is given by formula as :

Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\Q=15.5\times 4.184\times (43.2-90)\\\\Q=-3035.073\ J

So, the heat of 3035.073 J is removed from 15.5 g of water.

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Which is most reactive out of calcium, potassium, and magnesium?
katen-ka-za [31]

Answer:

As we have already discussed, reactivity of alkali metals tends to increase as you go down the group. Therefore, sodium is less reactive with water than is potassium, likewise with the alkaline metals; calcium is more reactive than magnesium

5 0
2 years ago
How many moles are equal to 2.41x10 24 formula units of sodium chloride?
ryzh [129]
There are 6.022 x 10^23 formula units per mole

2.41 x 10^24 / 6.022 x 10^23 = 4.00 moles of Sodium Chloride

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3 0
4 years ago
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Burka [1]

Answer:

H2 is the limiting reactant.

Explanation:

From the diagram above:

H2 => White ball

O2 => Red ball

Before the reaction

H2 => White ball => 10

O2 => Red ball => 7

After the reaction

H2O => White and red ball => 10

O2 => 2

From the simple illustration above, we can see that all the H2 were used up in the reaction but there are left over of O2.

This simply means that H2 is the limiting reactant as all of it is used up in the reaction while O2 is the excess reactant as there are leftover.

7 0
3 years ago
What are the 6 steps to solving a mass-mass problem
aev [14]

Answer:

  • Write a balanced equation for the reaction.
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  • Convert mass of reactant to moles of reactant.
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  • Convert moles of product to grams of product.
  • Pick up the calculator and do the math.

Explanation:

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Answer:

F G there you go the guy on top is right

Explanation:

F G

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