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3 years ago

40 points for this question! Algebra 2. With all explanation, please!

Mathematics

1 answer:

const2013 [10]3 years ago

3 0

You will need three roots for this, so we have
Let x = -30, -10 and +20
So the factors will be (x+30)(x+10)(x-20)
The divide it to 100, this will help bring the peak up and down
So the polynomial function R(x) will become
1/100 * (x+30)(x+10)(x-20)
R(x) = 1/100 * (x+30)(x+10)(x-20)

Finding the X-intercept:
Let R(x) = 0 and solve for x.
1/100 * (x+30)(x+10)(x-20) = 0
x = -30, -10, 20 are the x-intercepts.

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A large data sample of heights of US women is normally distributed with a mean height of 64.7 inches and a standard deviation of

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Answer:0.16

Step-by-step explanation:

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3 years ago

What is the point-slope form of a line with slope -5 that contains the point<br> a<br> (2,-1)?

gulaghasi [49]

The point-slope form the line which has the value of slope -5 and contains a point as A(2,-1) is (y+1)=-5(x-2).

<h3>What is point slope form?</h3>

The point slope form of a line is the expression of line which has a specified slope and passes through a point.

The point slope form is givne as,

(y-y₁)=m(x-x₁)

Here, m is the slope of the line, x₁ is the x coordinate of the point by which line passes and y₁ is the y coordinate of the same point.

The slope of a line is -5. This line contains the point A (2,-1). Thus, the point slope form is,

(y-y₁)=m(x-x₁)

(y-(-1))=-5(x-2)

(y+1)=-5(x-2)

Thus, the point-slope form the line which has the value of slope -5 and contains a point as A(2,-1) is (y+1)=-5(x-2).

Learn more about the point slope form here;

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1 year ago

EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =

geniusboy [140]

The Lagrangian,

$L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)$

has critical points where its partial derivatives vanish:

$L_x=1-\lambda-2\mu x=0$

$L_y=2+\lambda-2\mu y=0$

$L_z=9-\lambda=0$

$L_\lambda=x-y+z-1=0$

$L_\mu=x^2+y^2-1=0$

$L_z=0$ tells us $\lambda=9$ , so that

$L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu$

$L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}$

Then with $L_\mu=0$ , we get

$x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2$

and $L_\lambda=0$ tells us

$x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}$

Then there are two critical points, $\left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right)$ . The critical point with the negative $x$ -coordinates gives the maximum value, $9+\sqrt{185}$ .

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3 years ago

The probability of a customer arrival at a grocery service counter in any one second is equal to 0.3. Assume that customers arri

Svetllana [295]

Answer:

Step-by-step explanation:

Given that the probability of a customer arrival at a grocery service counter in any one second is equal to 0.3

Assume that customers arrive in a random stream, so an arrival in any one second is independent of all others.

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a) the probability that the first arrival will occur during the third one-second interval.

= Prob that customer did not arrive in first 2 seconds * prob customer arrive in 3rd sec

= $0.7^2 (0.3)\\= 0.147$

b) the probability that the first arrival will not occur until at least the third one-second interval.

Prob that customer did not arrive in first two seconds *(Prob customer arrives in 3rd or 4th or 5th.....)

= $(0.7^2)[0.3+0.7*0.3+0.7^2*0.3+....)\\$

The term inside bracket is a geometric infinite progression with common ratio - 0.7 <1

Hence the series converges

Prob = $0.7^2 *\frac{0.3}{1-0.7} \\=0.49$

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3 years ago

In triangle DEF, CG = (x + 5) units and DG = (3x - 2) units.

Snowcat [4.5K]

Answer:

34 units

Step-by-step explanation:

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3 years ago

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