Answer:
Mk! I will when I get my account back!
Step-by-step explanation:
A(-7,-4) B(-2,0)
√[(x'-x)^2+(y'-y)^2]
√(-2-(-7)^2+(0-(-4)^2
√(5^2)+(4^2)
√25+16
√41
the distance is approximately 6.4 units
Answer:
Using the equation y = abx , substitute both of your given points into that equation.
2 = ab2 and 4 = ab3 Solve each equation for a.
2⁄b2 and 4⁄b3 = a Therefore, 2⁄b2 = 4⁄b3
Cross multiply: 2b3 = 4b2 Divide both sides by b2
2b = 4 a = 2/4 = 1/2
b = 2
y = 1 (2)x
2
Step-by-step explanation:
Answer:
A. Orthocenter
Step-by-step explanation:
In the given triangle, ΔWKS, the drawing shown the construction of a perpendicular line to the side KS that pass through the vertex <em>W </em>of ΔWKS. Therefore, the completed construction gives an altitude of the triangle ΔWKS
Repeating the same procedure from the vertex <em>S</em> to construct the perpendicular line (altitude) to the side WK, and from the vertex <em>K</em> the perpendicular line (altitude) to the side WS gives the three altitudes of the triangle
The point of intersection (the point of concurrency) of the three altitudes is the <em>orthocenter </em>of the triangle and the drawing would therefore be a step in finding the <em>orthocenter </em>of a triangle.
