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3 years ago

For the formation of ammonia, NH3, the enthalpy of reaction is shown:

Chemistry

1 answer:

Nataly [62]3 years ago

4 0

<u>Answer:</u> The amount of energy required to convert ammonia back to hydrogen and nitrogen is 45.9 kJ

<u>Explanation:</u>

Endothermic reactions are defined as the reactions in which energy is absorbed in the reaction. The enthalpy change of the reaction is positive.

Exothermic reactions are defined as the reactions in which energy is released in the reaction. The enthalpy change of the reaction is negative.

For the given chemical equation:

$3H_2(g)+N_2(g)\rightarrow 2NH_3(g);\Delta H=-45.9kJ$

In the above reaction, the enthalpy change is negative. So, the reaction is exothermic in nature.

For the reverse reaction, the magnitude of the enthalpy change remains the same but sign for it changes.

Hence, the amount of energy required to convert ammonia back to hydrogen and nitrogen is 45.9 kJ

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$\text{Moles of }CO_2=\frac{\text{Volume of }CO_2}{\text{Volume at STP}}=\frac{75}{22.4}=3.35mole$

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Now we have to calculate the mole fraction of $CO_2$ .

$\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CO_2+\text{Moles of }N_2}$

$\text{Mole fraction of }CO_2=\frac{3.35}{3.35+1.12}=0.75$

Now we have to calculate the partial pressure of the $CO_2$ gas.

$\text{Partial pressure of }CO_2=\text{Mole fraction of }CO_2\times \text{Total pressure of gas}$

$\text{Partial pressure of }CO_2=0.75mole\times 300Kpa=225Kpa=225Kpa\times \frac{0.145\text{ psia}}{1Kpa}=32.625\text{ psia}$

conversion used : (1 Kpa = 0.145 psia)

Therefore, the partial pressure of the $CO_2$ in the tank in psia is, 32.6 psia.

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