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Dafna1 [17]
3 years ago
10

For the formation of ammonia, NH3, the enthalpy of reaction is shown:

Chemistry
1 answer:
Nataly [62]3 years ago
4 0

<u>Answer:</u> The amount of energy required to convert ammonia back to hydrogen and nitrogen is 45.9 kJ

<u>Explanation:</u>

Endothermic reactions are defined as the reactions in which energy is absorbed in the reaction. The enthalpy change of the reaction is positive.

Exothermic reactions are defined as the reactions in which energy is released in the reaction. The enthalpy change of the reaction is negative.

For the given chemical equation:

3H_2(g)+N_2(g)\rightarrow 2NH_3(g);\Delta H=-45.9kJ

In the above reaction, the enthalpy change is negative. So, the reaction is exothermic in nature.

For the reverse reaction, the magnitude of the enthalpy change remains the same but sign for it changes.

Hence, the amount of energy required to convert ammonia back to hydrogen and nitrogen is 45.9 kJ

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For SCl4, the electron domain geometry is _______(i)________ and the molecular geometry is ______(ii)________.
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Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici
irina1246 [14]

Answer:

                     2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

Explanation:

Step 1: Write the unbalanced chemical equation,

                          C₄H₁₀ + O₂ → CO₂ + H₂O

Step 2: Balance Carbon  Atoms;

As there are 4 carbon  atoms on left hand side and 1 carbon atoms on right hand site therefore, to balance them multiply CO₂ on right hand side by 4 i.e.

                            C₄H₁₀ + O₂ → 4 CO₂ + H₂O

Step 3: Balance Hydrogen Atoms;

There are 10 hydrogen atoms on left hand side and 2 hydrogen atom on right hand site therefore, to balance them multiply H₂O on left hand side by 5 i.e.

                            C₄H₁₀ + O₂ → 4 CO₂ +  5 H₂O

Step 4: Balance Oxygen Atoms:

Now there are 2 oxygen atoms in reactant side and 13 in product side. So, multiply O₂ by 6.5 i.e.

                            C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O

Step 5: Remove fraction coefficients as,

Multiply whole equation by 2 to get rid of fractions i.e.

                            2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

7 0
3 years ago
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