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Anit [1.1K]
2 years ago
12

A 3.5 gram sample of a radioactive element was formed in a 1960 explosion of an atomic bomb at Johnson Island in the Pacific tes

t site. The half-life of the radioactive element is 28 years. How much of the original sample will remain in the year 2030? Show your work.
Chemistry
1 answer:
Annette [7]2 years ago
5 0
The answer is 0.62g.
Solution:
From year 1960 to year 2030, it has been 
     2030-1960 = 70 years

The half-life of the radioactive element is 28 years, then the sample will go through
     70 years * (1 half-life/28 years) = 2.5 half-lives

Starting with a 3.5 gram sample, we will have
     3.5*(1/2) after one half-life passes
     3.5*(1/2) * (1/2) = 3.5*(1/4) after two half-lives pass
     3.5*(1/4) * (1/2) = 3.5*(1/8) after three half-lives pass and so on

Therefore, we can write the remaining amount of the sample after the number n of half-lives have passed as
     mass of sample = initial mass of sample/2^n

The mass of the remaining sample for n = 2.5half-lives can be now calculated as
     mass of sample = 3.5 grams / 2^2.5 = 0.62 g
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The optimal pH is 6.9. The pancreatic amylase is a hydrolase secreted by pancreas and will go into the alimentary canal. The working environment has a pH of 6.9. So the optimal pH for the enzyme needs to be 6.9.
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2 years ago
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If the concentration of products is increased the equilibrium is shifted from * left to right/ to the left/ right to left /down
Marysya12 [62]

Answer:

to the left

Explanation:

<u>If the concentration of products is increased for a reaction that is in equilibrium, the equilibrium would shift to the left side of the reaction (the reactant's side). </u>

For a reaction that is in equilibrium, the reaction is balanced between the reactants and the products. According to Le Cha telier's  principle, if one of the constraints capable of influencing the rate of reactions is applied to such a reaction that is in equilibrium, the equilibrium would shift so as to neutralize the effects created by the constraint.

<em>Hence, in this case, if the concentration of the products of a reaction in equilibrium is increased, the equilibrium would shift in such a way that more reactants are formed so as to annul the effects created by the increase in the concentration of the products. Since reactants are always on the left side of chemical equations, it thus means that the equilibrium would shift to the left.</em>

5 0
2 years ago
An organic compound is 61.5% C, 2.56% H and 35.9% N by mass. 2.00 grams of this gas is entered into a 300.0 mL flask and heated
pashok25 [27]

Answer:

C₄H₂N₂

Explanation:

First we<u> calculate the moles of the gas</u>, using PV=nRT:

P = 2670 torr ⇒ 2670/760 = 3.51 atm

V = 300 mL ⇒ 300/1000 = 0.3 L

T = 228 °C ⇒ 228 + 273.16 = 501.16 K

  • 3.51 atm * 0.3 L = n * 0.082atm·L·mol⁻¹·K⁻¹ * 501.16 K
  • n = 0.0256 mol

Now we<u> calculate the molar mass of the compound</u>:

  • 2.00 g / 0.0256 mol = 78 g/mol

Finally we use the percentages given to<em> </em><u>calculate the empirical formula</u>:

  • C ⇒ 78 g/mol * 61.5/100 ÷ 12g/mol = 4
  • H ⇒ 78 g/mol * 2.56/100 ÷ 1g/mol = 2
  • N ⇒ 78 g/mol * 35.9/100 ÷ 14g/mol = 2

So the empirical formula is C₄H₂N₂

6 0
3 years ago
Si una masa dada de hidrógeno ocupa 40 litros a 700 grados torr. ¿Qué volumen ocupará a 1 atmósfera de presión? (dar la presión
Svetach [21]

Answer:

V_2=36.84L

Explanation:

Hola,

En este caso, podemos usar la ley de Boyle, la cual nos permite analizar el comportamiento volumen-presión en un gas ideal de manera inversamente propocional:

P_1V_1=P_2V_2

Así, dado el volumen y la presión inicial, la cual se convierte a atmósferas (760 torr = 1atm), calculamos el volumen final a 1 atm como se muestra a continuación:

V_2=\frac{P_1V_1}{P_2}=\frac{700torr*\frac{1atm}{760torr}*40l }{1atm}\\  \\V_2=36.84L

Saludos!

7 0
3 years ago
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What is the hardest metal?
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Answer:

i believe it is titanium.

Explanation:

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2 years ago
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