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Anit [1.1K]
2 years ago
12

A 3.5 gram sample of a radioactive element was formed in a 1960 explosion of an atomic bomb at Johnson Island in the Pacific tes

t site. The half-life of the radioactive element is 28 years. How much of the original sample will remain in the year 2030? Show your work.
Chemistry
1 answer:
Annette [7]2 years ago
5 0
The answer is 0.62g.
Solution:
From year 1960 to year 2030, it has been 
     2030-1960 = 70 years

The half-life of the radioactive element is 28 years, then the sample will go through
     70 years * (1 half-life/28 years) = 2.5 half-lives

Starting with a 3.5 gram sample, we will have
     3.5*(1/2) after one half-life passes
     3.5*(1/2) * (1/2) = 3.5*(1/4) after two half-lives pass
     3.5*(1/4) * (1/2) = 3.5*(1/8) after three half-lives pass and so on

Therefore, we can write the remaining amount of the sample after the number n of half-lives have passed as
     mass of sample = initial mass of sample/2^n

The mass of the remaining sample for n = 2.5half-lives can be now calculated as
     mass of sample = 3.5 grams / 2^2.5 = 0.62 g
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Describe why an element's physical properties are different from its chemical properties. Include in your answer an example of o
Contact [7]

Answer:

Explanation:

Hello,

At first, they differ because a physical property is observed without changing the nature of the substance. On the other hand, a change in the nature of the substance must be carried out to observe a chemical property.

As examples, density, solubility and odor (physical properties) could be known by just analyzing a substance, nonetheless, pH, reactivity or combustibility must be known by submitting the substance to a specific chemical reaction.

Best regards.

4 0
3 years ago
If the element A have three protons in the nucleus. find the atomic number of the element A​
sweet-ann [11.9K]

Answer:

ATOMIC number of element A is 3

Explanation:

Atomic number is the same as number of protons of an element.

according to the periodic table, Lithium is the element with 3 protons in its neutral state and it's atomic number is 3.

3 0
2 years ago
50.0 ml of 0.010m naoh was titrated with 0.50m hcl using a dropper pipet. if the average drop from the pipet has a volume of 0.0
creativ13 [48]

25 drops of acid is required to neutralize the 50.0 ml of 0.010m of NaOH in the experiment.

The equation of the reaction is;

NaOH(aq) + HCl(aq) ---------> NaCl(aq) + H2O(l)

We can use the titration formula;

CAVA/CBVB = NA/NB

CA= concentration of acid

VA = volume of acid

CB = concentration of base

VB = volume of base

NA = number of moles of acid

NB = number of moles of base

CB = 0.010 M

VB = 50.0 ml

CA = 0.50 M

VA = ?

NA = 1

NB = 1

Substituting values;

CAVANB = CBVBNA

VA =  0.010 ×  50.0 × 1/ 0.50 × 1

VA = 1 ml

Since the total volume of acid used is 1 ml and each drop contains 0.040 ml

The number of drops required is 1ml/0.040 ml = 25 drops

Learn more: brainly.com/question/1527403

4 0
3 years ago
Can anyone help with Standard Cell Potential?​
Shkiper50 [21]

Answer:

its A

Explanation:

7 0
3 years ago
For the set of ionic compounds, LiCl, AgCl, PbCl2, choose the correct characterization of their solubilities in water from the r
sergiy2304 [10]

Answer:

Two of the three salts are soluble.

One of the three salts is soluble.

Explanation:

<em>One or two of the three salts would be soluble in water depending on if the water is cold or hot.</em>

<u>According to the solubility rules of chloride salts, all chlorides are soluble in cold water except for those of silver (Ag), lead (Pb), and mercury (I) (Hg). </u>

This thus means that both AgCl and PbCl_2 would be insoluble in cold water while LiCl would be soluble.

PbCl_2 is, however soluble in hot water.

Hence, in cold water, one of the three salts (LiCl) would be soluble, while in hot water, two of the three salts (LiCl and PbCl_2) would be soluble.

7 0
3 years ago
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