How many kilojoules of heat energy are absorbed when 98.5 g of water are heated from 24.5 oC to 48.8 oC?
1 answer:
Answer:
10.01461 kilojoules of thermal energy are absorbed when 98.5 g of water is heated from 24.5 ° C to 48.8 ° C
Explanation:
Sensible heat is the amount of heat that a body absorbs or releases without any changes in its physical state (phase change) causing a change in temperature.
The equation that allows to calculate heat exchanges in this case is:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the change in temperature.
In this case:
- c=4.184
- m= 98.5 g
- ΔT= Tfinal - Tinitial= 48.8°C - 24.5°C= 24.3 °C
Replacing:
Q= 4.184 *98.5 g* 24.3 °C
Solving:
Q=10,014.61 J
Since 1 J is equal to 0.001 kJ, then you can apply the following rule of three: if 1 J is equal to 0.001 kJ, then 10,014.61 J is equal to how many kJ?
kJ=10.01461 kJ
<u><em>10.01461 kilojoules of thermal energy are absorbed when 98.5 g of water is heated from 24.5 ° C to 48.8 ° C</em></u>
You might be interested in
Answer:
See Explanation
Explanation:
In electrophilic aromatic substitution, the benzene ring undergoes substitution when it is reacted with suitable electrophiles.
The products of electrophilic aromatic substitution depends on the substituents already present on the benzene ring. Some substituents activate the ring towards electrophilic substitution and direct the incoming electrophile to the ortho and para positions on the ring while some substituents deactivate the benzene ring towards electrophilic substitution and direct the incoming electrophlle to the meta position on the ring.
The amide substituent is moderately activating and is an ortho, para director hence the products shown in the mage attached to this answer.
