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professor190 [17]
4 years ago
11

How many moles of sodium metal are needed to make 3.6 moles of sodium chloride? Given the reaction: 2Na + Cl2 → 2NaCl

Chemistry
2 answers:
snow_lady [41]4 years ago
7 0

Answer:

3.6 moles of Na

Explanation:

Reaction is this one:

2Na + Cl₂ → 2NaCl

Ratio is 2:2, so 3.6 moles of NaCl could come from 3.6 moles of Na,

If we have to convert the mass to moles

3.6 mol . 23 g/mol = 82.8 g

Arisa [49]4 years ago
3 0

Answer:

3.6 moles

Explanation:

2Na + Cl2 → 2NaCl

From the balanced chemical equation above, we can tell that 2 mole of Sodium Metal reacts with 1 mole of Chlorine molecule to form 2 mole of sodium chloride.

How many moles would then form 3.6 moles of sodium chloride?

2 mol = 2 mol

x mol = 3.6 mol

Upon solving for x, we have;

x = (3.6 * 2) / 2

x = 3.6 mol

This means that 3.6 moles of sodium metal would be needed to make 3.6 moles of sodium chloride

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g A radioactive isotope of mercury, 197Hg, decays to gold, 197Au, with a disintegration constant of 0.0108hrs.-1. What % of the
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Answer:

7.49% of Mercury

Explanation:

Let N₀ represent the original amount.

Let N represent the amount after 10 days.

From the question given above, the following data were obtained:

Rate of disintegration (K) = 0.0108 h¯¹

Time (t) = 10 days

Percentage of Mercury remaining =?

Next, we shall convert 10 days to hours. This can be obtained as follow:

1 day = 24 h

Therefore,

10 days = 10 day × 24 h / 1 day

10 days = 240 h

Thus, 10 days is equivalent to 240 h.

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Time (t) = 10 days

Percentage of Mercury remaining =?

Log (N₀/N) = kt /2.303

Log (N₀/N) = 0.0108 × 240 /2.303

Log (N₀/N) = 2.592 / 2.303

Log (N₀/N) = 1.1255

Take the anti log of 1.1255

N₀/N = anti log 1.1255

N₀/N = 13.3506

Invert the above expression

N/N₀ = 1/13.3506

N/N₀ = 0.0749

Multiply by 100 to express in percent.

N/N₀ = 0.0749 × 100

N/N₀ = 7.49%

Thus, 7.49% of Mercury will be remaining after 10 days

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