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Lady bird [3.3K]

3 years ago

6

Jenny plans to have two children but doesn't know if they will be boy-boy, girl-girl, or boy-girl. What is the probability that

she will have two boys?
0.5
0.25
0.75
1.00

2 answers:

Serggg [28]3 years ago

8 0

The probability of Jenny having two boys is 0.25

lubasha [3.4K]3 years ago

3 0

B G

B <u>BB</u> BG

G GB GG

.25

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Kiko and mato each took out a loan for $5,000 from the bank. kika has an interest rate of 5.2% and he plans to repay the loan in

miv72 [106K]

It will be b : KikaKika 700:

Step-by-step explanation:

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2 years ago

What is the slope of the line represented by the points in the table?

kotykmax [81]

To find the slope(m) of the line, you can use the slope formula:

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

and plug in 2 points.

You can use any of the points, I will be using the points (0, -0.25) and (1, -0.2)

$m = \frac{y_{2}-y_{1}}{y_{2}-x_{1}}$

$m = \frac{-0.2 - (-0.25)}{1-0}$

$m = \frac{-0.2 + 0.25}{1-0}$

$m = \frac{0.05}{1}$

m = 0.05 (The last answer)

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4 years ago

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Light travels at 2.998 x 10 miles per second. It takes

Olenka [21]

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3 years ago

16 more than s is at most −80.

polet [3.4K]

Answer:

s + 16 ≤ −80

Step-by-step explanation:

Analyze each part in the word equation:

"16 more than s" s increased by 16; s + 16

"is at most" is equal to or less than; ≤

"−80" -80

Put the equation back together:

s + 16 ≤ −80

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4 years ago

Suppose that a jewelry store tracked the amount of emeralds they sold each week to more accurately estimate how many emeralds to

RUDIKE [14]

Answer:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

5 0

3 years ago