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3 years ago

Find the inverse of (1/3y)-7 Please show work!

Mathematics

1 answer:

Pani-rosa [81]3 years ago

7 0

Answer:

Step-by-step explanation:

if additive inverse then

(1/3y)+7

if multiplicative inverse then

3y-7

if both then

3y+7

if in this way

f(x)=(1/3x)-7

f(-x)=(-1/3)-7

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-7X>10<br>solve for x answer musr be simplifyed<br>

Scrat [10]

Answer:

x < -10/7

Step-by-step explanation:

Divide both sides by -7. Because this divisor is negative, we must reverse the direction of the inequality sign, obtaining:

-7x < 10

----- < -----

-7 -7

Then x < -10/7

8 0

3 years ago

8−i

GalinKa [24]

Hi Veracity,

Answer:

(2 + i) = 2

Step-by-step explanation:

Multiply the denominator and numerator by the conjugate,

= $\frac{(8 - i)(3 + 2i)}{13}$

Combine Like Terms,

= $\frac{26 + 13i}{13}$

Simplify,

= 2 + i

Hope This Helps :)

3 0

2 years ago

Preform the subtraction: (5x^2 -3xy +10y^2) - (12x^2 +11xz- 7z^2)

Rzqust [24]

we are given

$(5x^2 -3xy +10y^2) - (12x^2+11xz-7z^2)$

we have to subtract

step-1: Distribute negative sign

$=5x^2 -3xy +10y^2-12x^2-11xz+7z^2$

step-2:Combine like terms

$=5x^2 -12x^2-3xy -11xz+10y^2+7z^2$

$=-7x^2-3xy -11xz+10y^2+7z^2$

we get

$=-7x^2-3xy -11xz+10y^2+7z^2$ ............Answer

3 0

3 years ago

Solve the equation for x 1/3x - 15 = 12

Akimi4 [234]

X = 81
You are welcome

6 0

3 years ago

Read 2 more answers

Write y6 as a product of 2 powers with the same base in 4 differenct ways

topjm [15]

$y^{2}*y^{4}= y^{3}*y^{3}= y^{1}*y^{5}= y^{0}*y^{6}=y ^{6}$

4 0

3 years ago