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shutvik [7]
3 years ago
12

What two numbers multipy to 24 but add up to -4​

Mathematics
1 answer:
Nostrana [21]3 years ago
6 0

Answer:

none, it isn't possible.

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Solve and simplify 25 x 1/5 (thanks)
sammy [17]

Answer:

5

Step-by-step explanation:

First let turn 25 into a fraction

\frac{25}{1}*\frac{1}{5}

Multiply

\frac{25}{5}

Divide/Simplify

=5

Answer = 5

[RevyBreeze]

4 0
2 years ago
Multiply<br> (2x + 4)(2x - 4)
lakkis [162]

Answer:

4x^2 -16

Step-by-step explanation:

(2x + 4)(2x - 4)

FOIL

first:2x*2x = 4x^2

outer: -4 *2x = -8x

inner:  4*2x = 8x

last: -4*4 = -16

Add them together

4x^2 -8x+8x =-16

4x^2 -16

8 0
3 years ago
Read 2 more answers
(HURRY! I'M BEING TIMED)Write the partial fraction decomposition of the rational expression.
Aleonysh [2.5K]

Answer:

The partial fraction decomposition is \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}.

Step-by-step explanation:

Partial-fraction decomposition is the process of starting with the simplified answer and taking it back apart, of "decomposing" the final expression into its initial polynomial fractions.

To find the partial fraction decomposition of \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}:

First, the form of the partial fraction decomposition is

                                  \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{A}{x + 1}+\frac{B}{\left(x + 1\right)^{2}}+\frac{C}{x + 2}

Write the right-hand side as a single fraction:

                             \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B}{\left(x + 1\right)^{2} \left(x + 2\right)}

The denominators are equal, so we require the equality of the numerators:

             - 4 x^{2} + 13 x - 12=\left(x + 1\right)^{2} C + \left(x + 1\right) \left(x + 2\right) A + \left(x + 2\right) B

Expand the right-hand side:

           - 4 x^{2} + 13 x - 12=x^{2} A + x^{2} C + 3 x A + x B + 2 x C + 2 A + 2 B + C

The coefficients near the like terms should be equal, so the following system is obtained:

\begin{cases} A + C = -4\\3 A + B + 2 C = 13\\2 A + 2 B + C = -12 \end{cases}

Solving this system, we get that A=50, B=-29, C=-54.

Therefore,

                                  \frac{- 4 x^{2} + 13 x - 12}{\left(x + 1\right)^{2} \left(x + 2\right)}=\frac{50}{x + 1}+\frac{-29}{\left(x + 1\right)^{2}}+\frac{-54}{x + 2}

7 0
3 years ago
Please please please please please please help me a b c or d
DIA [1.3K]

Answer:

Answer is 70 degree

Option b. 70 degree

Step-by-step explanation:

please mark as brainliest.

Angle QPR= 90 degree

Therfore, Angle QPS= 90-20

= 70 degree

8 0
3 years ago
Read 2 more answers
Complete the square to rewrite y=x(squared)-6x+14 in vertex form.
WITCHER [35]
Y = x² - 6x + 14
y = x² - 6x + 3² - 3² -14
y = (x - 3)² - 9 - 14
y = (x - 3)² - 23

------------------------------------------------
Answer : y = (x - 3)² - 23
------------------------------------------------
4 0
3 years ago
Read 2 more answers
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