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Sonbull [250]
3 years ago
15

a landscaper is creating a rectangular flower bed such that the width is half of the length. The area of the flower bed is 34 sq

uare feet. Write and solve an equation to determine the width of the flower bed, to the nearest tenth of a foot
Mathematics
1 answer:
Blizzard [7]3 years ago
8 0
<span>As for this problem, we will first establish that the length of the flower bed be represented as x, the width of the flower bed be represented as x/2 ,and the area of the flower bed be taken as it is since it is given. We then follow the formula for area which is length multiplied to width which is:<span>
A = LW

we then substitute them

34 square feet = x (x/2)
now all we need to do is find x first.

34 square feet = x squared / 2
now do a cross multiplication

68 square feet = x squared
then get the square root of both sides

8.246 feet = x

Since x is equal to the length of the flower bed, all we have to do to get the width of it is to divide it by 2. So...

W = x/2
W = 8.246 feet / 2
W = 4.123 feet

<span>And since the problem asked it to find the width of the flower bed to the nearest tenth of a foot, the answer would be 4.1 ft.</span></span></span>
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Zarrin [17]

Answer:

Most likely B

Step-by-step explanation:

Most likely B because it starts up around 5 which is the y int of B

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A rectangular garden is 8 feet wide and 15 feet long. A diagonal path cuts through the entire garden. How long is the path?
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Let A be a set of numbers.
LUCKY_DIMON [66]

Answer:

a. closed under addition and multiplication

b. not closed under addition but closed under multiplication.

c. not closed under addition and multiplication

d. closed under addition and multiplication

e. not closed under addition but closed under multiplication

Step-by-step explanation:

a.

Let A be a set of all integers divisible by 5.

Let x,y∈A such that x=5m\,,\,y=5n

Find x+y,xy

x+y=5m+5n=5(m+n)

So, x+y is divisible by 5.

xy=(5m)(5n)=25mn=5(5mn)

So,

xy is divisible by 5.

Therefore, A is closed under addition and multiplication.

b.

Let  A = { 2n +1 | n ∈ Z}

Let x,y∈A such that x=2m+1\,,\,y=2n+1 where m, n ∈ Z.

Find x+y,xy

x+y=2m+1+2n+1=2m+2n+2=2(m+n+1)

So,

x+y ∉ A

xy=(2m+1)(2n+1)=4mn+2m+2n+1=2(2mn+m+n)+1

So,

xy∈ A

Therefore, A is not closed under addition but A is closed under multiplication.

c.

Let A=\{2,5,8,11,14,...\}

Let x=2,y=5 but x+y=2+5=7∉A

Also,

xy=2(5)=10∉A

Therefore, A is not closed under addition and multiplication.

d.

Let A = { 17n: n∈Z}

Let x,y ∈ A such that x=17n,y=17m

Find x + y and xy

x+y=17n+17m=17(n+m)

xy=(17m)(17n)=289mn=17(17mn)

So,

x+y,xy ∈ A

Therefore, A is closed under addition and multiplication.

e.

Let A be the set of nonzero real numbers.

Let x,y ∈ A such that x=-1,y=1

Find x + y

x+y=-1+1=0

So,

x+y ∈ A

Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.

Therefore, A is not closed under addition but A is closed under multiplication.

4 0
2 years ago
Solve for a. 1/5(25−5a)=4−a
aalyn [17]
1/5(25-5a)=4-a
⇔5-a=4-a
<span>NO SOLUTION</span>
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3 years ago
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