Answer:
A. square root of a^2 + b^2 for both answers
Step-by-step explanation:
The first problem, we are given
a^2 + b^2 = c^2
What we do is solve for c.
sqrt(a^2 + b^2) = c
c = sqrt(a^2 + b^2)
For problem 2,
WE can apply the Pythagorean theorem because we have a right triangle.
The equations is
a^2 + b^2 = c^2 like the first problem
Solving gets us
sqrt(a^2 + b^2) = c
c = sqrt(a^2 + b^2)
Answer: -74
Step-by-step explanation:
First you have to solve - 2y - 9 = 7 to find what "y" equals so we can plug that into 9y - 2
1. Solve -2y - 9 =7:
-2y = 16
y = -8
2. Plug -8 into the expression 9y - 2:
9(-8) - 2
-72 -2
-74!
Im sorry if i didnt do this correctly :/
Answer:
landing on a shaded portion and landing on an even number
; landing on a shaded portion and landing on a number greater than 3
; landing on an unshaded portion and landing on an odd number
; and landing on an unshaded portion and landing on a number less than 2.
Explanation:
Mutually exclusive events are events that cannot occur at the same time. Our spinner has two grey sections, on 1 and 3; and two white sections, on 2 and 4.
This means that the spinner cannot land on a shaded (grey) portion and land on an even number at the same time, since the grey sections are numbered 2 and 4, both of which are even numbers.
The spinner also cannot land on a shaded (grey) portion and land on a number greater than 3 at the same time; this is because the only number greater than 3 on the spinner is 4, which is a white portion.
The spinner cannot land on an unshaded (white) portion and land on an odd number, since the white sections are labeled 2 and 4, which are both even.
The only number on the spinner less than 2 is 1, which is grey; this means the spinner cannot land on a number less than 2 and an unshaded (white) portion at the same time.
Easy peasy, this is a representation of differnce of 2 perfect squares
a^2-b^2=(a-b)(a+b)
The sixth term of an arithmetic sequence is 6
<h3>How to find arithmetic sequence?</h3>
The sum of the first four terms of an arithmetic sequence is 10.
The fifth term is 5.
Therefore,
sum of term = n / 2(2a + (n - 1)d)
where
- a = first term
- d = common difference
- n = number of terms
Therefore,
n = 4
10 = 4 / 2 (2a + 3d)
10 = 2(2a + 3d)
10 = 4a + 6d
4a + 6d = 10
a + 4d = 5
4a + 6d = 10
4a + 16d = 20
10d = 10
d = 1
a + 4(1) = 5
a = 1
Therefore,
6th term = a + 5d
6th term = 1 + 5(1)
6th term = 6
learn more on sequence here: brainly.com/question/24128922
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