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Jobisdone [24]
3 years ago
7

Using the sample in question 3, how many counts per second would be observed when the detector is 10 meters away from the sample

?
Physics
1 answer:
juin [17]3 years ago
3 0

It's hard for me to adequately express how much easier it would be to answer
this one if only I could see Question 3.

At the same time, I'm consumed with curiosity, and am at a loss to imagine
how you could post this question in good faith without telling us anything about
Question 3.  As you read this one, did you not notice that you need to know what's
in Question 3 before you can do anything with this one ?  Maybe that right there is
the whole source of the difficulty you may be having with this one. 

Take my advice.  Please.  Go read Question 3.  

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What average net force is required to accelerate a 9.5 g
Nesterboy [21]

Answer:

2361 Newtons

Explanation:

From the second Newton's law of motion;

F = ma

In this case;

we are given;

Mass as 9.5 g

Initial speed as 0 m/s

Final velocity as 650 m/s

Distance is 0.85 m

Using the equation;

V² = U² + 2as

But u = 0

v² = 2as

Therefore;

a = v² ÷ 2s

  = 650² ÷ 2(0.85)

  = 248,529.40 m/s²

But;

F = ma

   = 0.0095 kg × 248,529.40 m/s²

   = 2361 Newtons

Therefore;

The average net force required to accelerate the bullet is 2361 Newtons.

6 0
3 years ago
How is energy sent from Earth to space?
Nostrana [21]
It might be radiation and reflection but I’m not sure
8 0
3 years ago
Read 2 more answers
Imagine you are sitting on a sled and someone is about to push you down a hill. Which statement is accurate?
Dima020 [189]

The answer is:

Forces acting on the sled are paired with equal and opposite forces.

The explanation:

About to push you, this means that he doesn't push yet. If the sled is on level ground and no one is pushing it, then forces are equal and opposite.

The gravity force pulls down and the ground pushes up.

This is Newton's third law:

Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.

We can also see Newton’s third law at work by taking a look at how people move about. Consider a swimmer pushing off from the side of a pool.

6 0
3 years ago
Read 2 more answers
A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling
Natalka [10]

Answer:

H = 5 m

Explanation:

As the person leaves the slide horizontally so the time taken by the person to hit the water is given as

t = 0.672 s

so we can find the vertical velocity by which person will hit the water using kinematics

v_y = u_y + at

v_y = 0 + (9.81)(0.672)

v_y = 6.6 m/s

now the speed of the person at the end of the slide is given as

v = \frac{L}{t}

v = \frac{5}{0.672}

v_x = 7.44 m/s

now by energy conservation we can find the initial height

mgH = \frac{1}{2}m(v_x^2 + v_y^2)

H = \frac{1}{2g}(v_x^2 + v_y^2)

H = \frac{1}{2(9.81)}(7.44^2 + 6.6^2)

H = 5 m

6 0
3 years ago
Read 2 more answers
Saturn has a radius of about 9.0 earth radii, and a mass 95 times the Earth’s mass. Estimate the gravitational field on the surf
torisob [31]

Answer:

11.49 m/s²

Explanation:

gs = gm/r²

gs = g(95 Me) / (9²Re²)

gs = ge × (95/9²)

gs = 1.173 × ge

gs = 1.173 × 9.8

gs = 11.49

The unit is m/s²

7 0
3 years ago
Read 2 more answers
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