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Jobisdone [24]
3 years ago
7

Using the sample in question 3, how many counts per second would be observed when the detector is 10 meters away from the sample

?
Physics
1 answer:
juin [17]3 years ago
3 0

It's hard for me to adequately express how much easier it would be to answer
this one if only I could see Question 3.

At the same time, I'm consumed with curiosity, and am at a loss to imagine
how you could post this question in good faith without telling us anything about
Question 3.  As you read this one, did you not notice that you need to know what's
in Question 3 before you can do anything with this one ?  Maybe that right there is
the whole source of the difficulty you may be having with this one. 

Take my advice.  Please.  Go read Question 3.  

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Why should it take significantly more energy to move a beam of alpha particles than a beam of beta minus (β–) particles?
a_sh-v [17]
An 'alpha particle' is the same thing as the nucleus of a helium atom ... 
a little bundle made of 2 protons and 2 neutrons.

A 'beta' particle is an electron.

The mass of an alpha particle is more than 7,000 times the mass of 
an electron, so it certainly takes more energy to get it moving.
4 0
3 years ago
Read 2 more answers
How is the work done to hoist the counterweight related to the potential energy of the counterweight at its specified height?
Nesterboy [21]

Answer:

The work done to lift the counterweight equals the potential energy acquired

Explanation:

since this is vertically applied force on the counterweight, and the distance the force is displacing the counterweight is in the same direction as the applied force, it equals the gained potential energy

3 0
3 years ago
Which of these is true for the two poles of a magnet?
mina [271]
The correct answer to this problem would be that like poles repel and unlike poles attract.

N and N poles repel
S and S poles repel
N and S poles attract
S and N poles attract

Answer: D) like poles repel each other. unlike poles attract each other

I hope this helps!
3 0
4 years ago
Read 2 more answers
A substance with a density of 16.8 g/ml has a mass of 3.2 g. what is its volume?
wel
We know that d=m/v where d is density, m is mass and v is volume. Lets transform formula to get v in times of d and m
d= \frac{m}{V}  /*V \\ V*d=m /:d \\ V= \frac{m}{d}
Now we have to substitute our data to formula
V=\frac{3.2}{16.8}=0.19 ml - its the answeer
4 0
3 years ago
Read 2 more answers
What impulse occurs when an average force of 20-N is applied by a dad to a new bike riding child for 3.5 s. b) What change in mo
garri49 [273]

Answer:

A. 70 Ns

B. 70 Kgm/s

C. 2.19 m/s

Explanation:

A. Determination of the impulse.

Force (F) = 20 N

Time (t) = 3.5 s

Impulse (I) =?

Impulse (I) = force (F) × time (t)

I = Ft

I = 20 × 3.5

I = 70 Ns

Thus, the Impulse is 70 Ns.

B. Determination of the change in momentum

Force (F) = 20 N

Time (t) = 3.5 s

Change in momentum =?

Change in momentum = m(v – u) = Ft

Change in momentum = Ft

Change in momentum = 20 × 3.5

Change in momentum = 70 Kgm/s

C. Determination of the final velocity.

Change in momentum = 70 Kgm/s

Initial velocity (u) = 0 m/s

Combined mass (m) = 32 kg

Final velocity (v) =?

Change in momentum = m(v – u)

70 = 32(v – 0)

70 = 32(v)

70 = 32v

Divide both side by 32

v = 70 / 32

v = 2.19 m/s

Thus, the final velocity is 2.19 m/s

3 0
3 years ago
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