Answer:
The kinetic energy of the weight is 344.5 J
Explanation:
Given that:
Force = F = 65 newton
distance = d = 5.3 meters
We have to find change in kinetic energy ΔK.E
Now we know that, initially kinetic energy was 0 So the formula we use will be:
Work done = Change in kinetic energy
Mathematically,
W = ΔK.E
As we know W = F . d and ΔK.E = K.E(final) - K.E(initial)
So by putting values:
F . d = K.E(final) - K.E(initial)
F . d = K.E(final)
As K.E(initial) is 0 so by putting values of F and d
(65)* (5.3) = K.E(final)
344.5 J = K.E(final)
So the change in K.E will also be 344.5 J
i hope it will help you!
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Answer:
248.756 mV
49.7265 µA
Explanation:
The Thevenin equivalent source at one terminal of the bridge is ...
voltage: (100 V)(1000/(1000 +1000) = 50 V
impedance: 1000 || 1000 = (1000)(1000)/(1000 +1000) = 500 Ω
The Thevenin equivalent source at the other terminal of the bridge is ...
voltage = (100 V)(1010/(1000 +1010) = 100(101/201) ≈ 50 50/201 V
impedance: 1000 || 1010 = (1000)(1010)/(1000 +1010) = 502 98/201 Ω
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The open-circuit voltage is the difference between these terminal voltages:
(50 50/201) -(50) = 50/201 V ≈ 0.248756 V . . . . open-circuit voltage
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The current that would flow is given by the open-circuit voltage divided by the sum of the source resistance and the load resistance:
(50/201 V)/(500 +502 98/201 +4000) = 1/20110 A ≈ 49.7265 µA
