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Ivan
3 years ago
12

A heavy ball with a weight of 100 N is hung from the ceiling of a lecture hall on a 4.3-m-long rope. The ball is pulled to one s

ide and released to swing as a pendulum, reaching a speed of 5.0 m/s as it passes through the lowest point. Part A What is the tension in the rope at that point?
Engineering
1 answer:
Vlada [557]3 years ago
6 0

Answer: T= 159.3N

Explanation:

The total Tension on the rope at this point=

Sum of the weight of the ball + the centripetal force on the ball

T= W+ mv^2/r

Where T is tension, W is weight of the ball, m is mass of the ball, r is radius of rotation, v is the velocity of rotation. g= acceleration due to gravity

W= 100N

m= W/g= 100/9.8 = 10.2kg

v= 5m/s

r= 4.3m

Therefore,

T= 100 + 10.2×5^2/4.3

T= 100 + 59.3

T= 159.3N

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4 number answer is correct.

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3 years ago
Air enters a turbine with a stagnation pressure of 900 kPa and a stagnation temperature of 658K, and it is expanded to a stagnat
bezimeni [28]

Answer:

12.332 KW

The positive sign indicates work done by the system ( Turbine )

Explanation:

Stagnation pressure( P1 ) = 900 kPa

Stagnation temperature ( T1 ) = 658K

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mass flow rate ( m ) = 0.04 kg/s

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Assuming a steady state condition

( p1 / p2 )^(r-1/r)  = ( T1 / T2 )

= (900 / 100)^(1.4-1/1.4) = ( 658 / T2 )

=  ( 9 )^0.285 = 658 / T2

∴ T2 = 351.22 K

Finally Turbine Power / power developed can be calculated as

Wt = mCp ( T1 - T2 )

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6 0
2 years ago
John has just graduated from State University. He owes $35,000 in college loans, but he does not have a job yet. The college loa
IRISSAK [1]

Answer:

The correct response is "821.88". A further explanation is given below.

Explanation:

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6 0
3 years ago
a vertical cylindrical container is being cooled in ambient air at 25 °C with no air circulation. if the initial temperature of
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Answer:

the surface heat-transfer coefficient due to natural convection during the initial cooling period.  = 4.93 w/m²k

Explanation:

check attachement for answer explanation

7 0
3 years ago
Read 2 more answers
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