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Ivan
3 years ago
12

A heavy ball with a weight of 100 N is hung from the ceiling of a lecture hall on a 4.3-m-long rope. The ball is pulled to one s

ide and released to swing as a pendulum, reaching a speed of 5.0 m/s as it passes through the lowest point. Part A What is the tension in the rope at that point?
Engineering
1 answer:
Vlada [557]3 years ago
6 0

Answer: T= 159.3N

Explanation:

The total Tension on the rope at this point=

Sum of the weight of the ball + the centripetal force on the ball

T= W+ mv^2/r

Where T is tension, W is weight of the ball, m is mass of the ball, r is radius of rotation, v is the velocity of rotation. g= acceleration due to gravity

W= 100N

m= W/g= 100/9.8 = 10.2kg

v= 5m/s

r= 4.3m

Therefore,

T= 100 + 10.2×5^2/4.3

T= 100 + 59.3

T= 159.3N

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3 years ago
Compute the solution to x + 2x + 2x = 0 for Xo = 0 mm, vo = 1 mm/s and write down the closed-form expression for the response.
Nutka1998 [239]

Answer:

β = \frac{c}{\sqrt{km} } =  0.7071 ≈ 1 ( damping condition )

closed-form expression for the response is attached below

Explanation:

Given :  x + 2x + 2x = 0   for Xo = 0 mm and Vo = 1 mm/s

computing a solution :

M = 1,

c = 2,

k = 2,

Wn = \sqrt{\frac{k}{m} }  = \sqrt{2}  

next we determine the damping condition using the damping formula

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3 years ago
A number 12 copper wire has a diameter of 2.053 mm. Calculate the resistance of a 37.0 m long piece of such wire.
Alinara [238K]

Answer:

R=1923Ω

Explanation:

Resistivity(R) of copper wire at 20 degrees Celsius is 1.72x10^-8Ωm.

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A= π * (2.053/1000)/2=3.31*10^-6

To calculate for the resistance (R):

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R=(1.72*10^8)*(37.0)/(3.31*10^-6)

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3 years ago
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3 years ago
A tool chest has 950 N weight that acts through the midpoint of the chest. The chest is supported by feet at A and rollers at B.
Mazyrski [523]

Answer:

P > 142.5 N  (→)

the motion sliding

Explanation:

Given

W = 959 N

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If we apply

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If  Ay = By

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3 years ago
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