Answer:
(a) 2.39 MPa (b) 3.03 kJ (c) 3.035 kJ
Explanation:
Solution
Recall that:
A 10 gr of air is compressed isentropically
The initial air is at = 27 °C, 110 kPa
After compression air is at = a450 °C
For air, R=287 J/kg.K
cv = 716.5 J/kg.K
y = 1.4
Now,
(a) W efind the pressure on [MPa]
Thus,
T₂/T₁ = (p₂/p₁)^r-1/r
=(450 + 273)/27 + 273) =
=(p₂/110) ^0.4/1.4
p₂ becomes 2390.3 kPa
So, p₂ = 2.39 MPa
(b) For the increase in total internal energy, is given below:
ΔU = mCv (T₂ - T₁)
=(10/100) (716.5) (450 -27)
ΔU =3030 J
ΔU =3.03 kJ
(c) The next step is to find the total work needed in kJ
ΔW = mR ( (T₂ - T₁) / k- 1
(10/100) (287) (450 -27)/1.4 -1
ΔW = 3035 J
Hence, the total work required is = 3.035 kJ
Answer:
<em>Hello There The Correct Answer is </em>A. At The Job Site.
Explanation:
Because the SDS must not used any kind of chemical Most chemicals used in the workplace have some hazard potential, and thus will be covered by the rule. ... Chemical manufacturers, importers, and distributors of hazardous chemicals are all required to provide the appropriate labels and material safety data sheets to the employers to whom they ship the chemicals. So That why is Opinion A.
The diameter of an 18 mm dine when expressed in micrometers is; 18000 micrometers
<h3>Conversion of Units</h3>
We are given the diameter of dime at 18 mm.
Now, from conversion of units between mm(millimeter) and micrometer, we know that;
1 millimeter = 1000 micrometer.
Thus, by proportion, 18 millimeter will be;
18 millimeters × 1000 micrometers/1 millimeter
>> 18000 micrometers
In conclusion, the diameter of the 18mm fine in micrometers is; 18000 micrometers
Read more about conversion of units at; brainly.com/question/8421470
Answer:
(a) 120 kW
(b) 800 kW
Explanation:
Given:
diameter: 1.5 m
length = 22 m
U = 5 m/s
temperature = 20°C
For water at 20°C, take ρ = 998 kg/m³ and µ = 0.001 kg/m⋅s
To find:
power in kW
(a) if the cylinder is parallel
Length / Diameter = L / D = 22 / 1.5 = 14.6 = 15
Re(L) = ρ*U*L / µ = 998 * 5 * 22 / 0.001 = 109780000 = 1.1E8
C(D.Frontal) ≈ 1.1
Force = F = 1.1 * ρ/2 * U² * π / 4 * D
= 1.1 (998 / 2) (5)²(π / 4)(1.5)²
= 1.1 * 499 * 25 * 0.785 * 2.25
= 24000 N
Power = Force * Displacement / time
= F * U
= 24000 * 5
= 120000
Power = 120 kW
b) if the cylinder is normal to the tow direction.
Re(L) = ρ*U*D / µ = 998 * 5 * 1.5 / 0.001 = 7485000 = 7.5E6
C(D.Frontal) ≈ 0.4
Force = F = 0.4 * ρ/2 * U² * D * L
= 0.4 (998 / 2) (5)²(1.5)(22)
= 164670 ≈ 165000
Power = Force * Displacement / time
= F * U
= 165000 * 5 = 825000
≈ 800 kW
Power = 800 kW
