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jok3333 [9.3K]
3 years ago
13

A bathtub faucet has a maximum flow rate of 3 gal/min. The tub is rectangular (3 ft long x 2 ft wide x 1.5 ft deep). Although th

e tub drain is plugged, water leaks out at 0.01 gal/min. There is an overflow opening which allows water to drain from the tub. The overflow opening is 1 ft above the bottom of the tub. How long will it take the tub to fill to 1 ft deep with the faucet on at its maximum flow rate? If the area of the overflow opening is 0.5 in2 and water drains with a velocity of 1.8 ft/sec, will the tub ever overflow if you turn the faucet on at the maximum flow rate? If so, how long will it take? (Note: since the overflow opening is very small, assume that water drains through the entire opening once the water is 1 ft deep).

Engineering
1 answer:
Anvisha [2.4K]3 years ago
3 0

Answer:

Time taken = 136.32 minutes

Explanation:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

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Explanation:

NB: kindly check below for the attached picture.

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7 0
3 years ago
A sand has a natural water content of 5% and bulk unit weight of 18.0 kN/m3. The void ratios corresponding to the densest and lo
Zinaida [17]

Answer:

Relative density = 0.545

Degree of saturation = 24.77%

Explanation:

Data provided in the question:

Water content, w = 5%

Bulk unit weight = 18.0 kN/m³

Void ratio in the densest state, e_{min} = 0.51

Void ratio in the loosest state, e_{max} = 0.87

Now,

Dry density, \gamma_d=\frac{\gamma_t}{1+w}

=\frac{18}{1+0.05}

= 17.14 kN/m³

Also,

\gamma_d=\frac{G\gamma_w}{1+e}

here, G = Specific gravity = 2.7 for sand

17.14=\frac{2.7\times9.81}{1+e}

or

e = 0.545

Relative density = \frac{e_{max}-e}{e_{max}-e_{min}}

= \frac{0.87-0.545}{0.87-0.51}

= 0.902

Also,

Se = wG

here,

S is the degree of saturation

therefore,

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or

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7 0
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