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lesantik [10]
3 years ago
15

Janine made a cylindrical vase in which the sum of the lateral area and area of one base

Mathematics
1 answer:
Vinil7 [7]3 years ago
5 0
Is this multiple choice

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2. A boy runs at a speed of 10m/s. How long does he take to cover a distance of 1.5 km?<br> 'D Focus
jek_recluse [69]

1500m=1.5km so 1500 divided by 10= 150s it takes 150s to cover a distance of 1.5km

5 0
3 years ago
If a set of school supplies cost $6.70, how much change do you get from $10.00?
aivan3 [116]
6.70-10.00=3.30
So you get $3.30 as change
5 0
3 years ago
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Drag the ordered pairs to match the points shown on the coordinate grid.
Kobotan [32]

Answer:

A) (3, 6)

B) (2, 3)

C) (4, 2)

D) (6, 0)

4 0
2 years ago
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2/3 +1 2/7 =<br> step and working out plz
ollegr [7]

Answer:

Step-by-step explanation:

1. Make 1 2/7 an improper fraction = 9/7

2. Multiply 7 on both numerator and denominator for 2/3 to make 14/21, and multiply 3 for both numerator and denominator for 9/7 to make 27/21.

3. Add them together. 14/21+27/21=41/21.

4. (Optional) If the question is asking for mixed numbers, 41/21 = 1 20/21.

3 0
2 years ago
A 50-gallon rain barrel is filled to capacity. It drains at a rate of 10 gallons per minute. Write an equation to show how much
makvit [3.9K]

Answer:

The quantity of water drain after x min is 50 (0.9)^{x}  

Step-by-step explanation:

Given as :

Total capacity of rain barrel = 50 gallon

The rate of drain = 10 gallon per minutes

Let The quantity of water drain after x min = y

Now, according to question

The quantity of water drain after x min = Initial quantity of water ×  (1-\dfrac{\textrm rate}{100})^{\textrm time}

I.e The quantity of water drain after x min = 50 gallon ×  (1-\dfrac{\textrm 10}{100})^{\textrm x}

or,  The quantity of water drain after x min = 50 gallon × (0.9)^{x}

Hence the quantity of water drain after x min is 50 (0.9)^{x}  Answer

4 0
3 years ago
Read 2 more answers
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