Pls help asap no wrong answers------------

Mathematics

1 answer:

miv72 [106K]3 years ago

6 0

Answer:

0.75, 1.25

Step-by-step explanation:

first we bring the line equation into the same format as the parabola equation (y = ...)

3x - y = 1

y = 3x - 1

now we can say for the intersection points both equations must have the same result.

4x² - 1 = 3x - 1

4x² - 3x = 0

x(4x - 3) = 0

there are only 2 possible cases to make this true :

x = 0

and 4x - 3 = 0

4x = 3

x = 3/4 = 0.75

for the y value let's use the easier equation (line) :

y = 3×3/4 - 1 = 9/4 - 4/4 = 5/4 = 1.25

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Let g(x) = 2x and h(x)= x^2 -4. find (g o h)(0)

finlep [7]

The answer is -8

====================================================

Explanation:

There are two ways to get this answer

Method 1 will have us plug x = 0 into h(x) to get
h(x) = x^2 - 4
h(0) = 0^2 - 4
h(0) = 0 - 4
h(0) = -4
Then this output is plugged into g(x) to get
g(x) = 2x
g(-4) = 2*(-4)
g(-4) = -8 which is the answer
This works because (g o h)(0) is the same as g(h(0)). Note how h(0) is replaced with -4
So effectively g(h(0)) = -8 which is the same as (g o h)(0) = -8

-----------------------

The second method involves a bit algebra first
Start with the outer function g(x). Then replace every x with h(x). On the right side, we will replace h(x) with x^2-4 because h(x) = x^2-4

g(x) = 2x
g(x) = 2( x )
g(h(x)) = 2( h(x) ) ... replace every x with h(x)
g(h(x)) = 2( x^2-4 ) ... replace h(x) on the right side with x^2-4
g(h(x)) = 2x^2-8
(g o h)(x) = 2x^2-8

Now plug in x = 0
(g o h)(x) = 2x^2-8
(g o h)(0) = 2(0)^2-8
(g o h)(0) = 2(0)-8
(g o h)(0) = 0-8
(g o h)(0) = -8

Regardless of which method you use, the answer is -8

5 0

3 years ago

Please solve -3x+12=48

choli [55]

Answer:

x = 12

Step-by-step explanation:

-3x+12=48

-12 -12

*subtract 12 from both sides

-3x = 36

-3x/3 = 36/3