Ask question

Ask question

All categories

2 years ago

5

Pamela Mello is paid on an incremental commission schedule. She is paid 2.6% on the first $70,000 and 3.4% on any sales over $70

,000. If her weekly sales volume was $83,600, what was her total commission (in $)?

1 answer:

Anarel [89]2 years ago

5 0

Step-by-step explanation:

2.6% at $70,000

3.4% at $83,600 - $70,000

3.4% at $13,600

$x=0.026(70000)+70000+0.034(13600)+13600$

x = $85,882.40

You might be interested in

erastovalidia [21]

Answer:

D .

Sorry if i'm wrong.

$x(2 {x}^{2} + 4x - 1 )\\ = 2 {x}^{3} + 4 {x}^{2} - x$

6 0

2 years ago

A tree is 4.5 feet tall. It is expected to grow by 1.75

PtichkaEL [24]

Answer:

20.28571428571429

Step-by-step explanation:

6 0

2 years ago

Brielle made a color using 2 cups of white paint and 3

Rudiy27

Answer:

she should mix 6 cups of green paint with 4 cups of white paint

Step-by-step explaination:

you are just multiplying by 2. 2 times 2=4 cups of white paint. So the same thing you do to both sides, 2 times 3=6

so the answer is 6 cups of green paint

4 0

2 years ago

HALP. First answer brainliest

Rom4ik [11]

Answer:

5.68

Step-by-step explanation:

it is 5.67812

I just rounded the answer like is says to

8 0

2 years ago

Read 2 more answers

A financial talk show host claims to have a 55.3 % success rate in his investment recommendations. You collect some data over th

baherus [9]

Answer:

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

Step-by-step explanation:

For each recommendation, there are only two possible outcomes. Either it was a success, or it was a failure. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$p = 0.553, n = 10$

If the claim is correct and the performance of recommendations is independent, what is the probability that you would have observed 4 or fewer successful:

This is

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.553)^{0}.(0.447)^{10} = 0.0003$

$P(X = 1) = C_{10,1}.(0.553)^{1}.(0.447)^{9} = 0.0039$

$P(X = 2) = C_{10,2}.(0.553)^{2}.(0.447)^{8} = 0.0219$

$P(X = 3) = C_{10,3}.(0.553)^{3}.(0.447)^{7} = 0.0724$

$P(X = 4) = C_{10,4}.(0.553)^{4}.(0.447)^{6} = 0.1567$

$P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0003 + 0.0039 + 0.0219 + 0.0724 + 0.1567 = 0.2552$

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

3 0

2 years ago