Answer:
The distance between the ship at N 25°E and the lighthouse would be 7.26 miles.
Step-by-step explanation:
The question is incomplete. The complete question should be
The bearing of a lighthouse from a ship is N 37° E. The ship sails 2.5 miles further towards the south. The new bearing is N 25°E. What is the distance between the lighthouse and the ship at the new location?
Given the initial bearing of a lighthouse from the ship is N 37° E. So,
is 37°. We can see from the diagram that
would be
143°.
Also, the new bearing is N 25°E. So,
would be 25°.
Now we can find
. As the sum of the internal angle of a triangle is 180°.

Also, it was given that ship sails 2.5 miles from N 37° E to N 25°E. We can see from the diagram that this distance would be our BC.
And let us assume the distance between the lighthouse and the ship at N 25°E is 
We can apply the sine rule now.

So, the distance between the ship at N 25°E and the lighthouse is 7.26 miles.
Answer:
Step-by-step explanation:
Slope = 0
y-y1=m(x-x1)
y-3=0
y = 3
I have nooo clue the problem doesn’t make sense
Answer:
2 cans
Step-by-step explanation:
1/2 + 1/4 + 4/5 = 1.55
2 is the best answer since we know the cat eats more than 1 and a half cans so the closest thing would be 2 cans
Answer: ...
Step-by-step explanation: