Y=x-7 this is because you subtracted the x to both sides. Since y is a negative, you divide by -1 causing the -x to turn positive and the positive seven to be negative seven.
Well, 4 cups = 1 quart, so 4 *6= 24 cups in 6 quarts of lemonade.
Answer:
The entire area of the sailboat is 60cm²
Step-by-step explanation:
You can find the area of this shape by breaking it down into simpler shapes and adding up their individual areas.
In this case, the areas we'll use are the rectangle at the bottom, and the pair of triangles at the top.
Because the two triangles can be put together to form a single triangle, we don't need to measure them independently. We can simply take the total length of their bases, multiply it by their height, and divide by two. This follows the rule that the area of a triangle is equal to the area of the square that contains it divided by two.
(2cm + 3cm) × 6cm
= 5cm × 6cm
= 30cm²
The rectangle's area is of course equal to its width times its height, so we can say:
2.5cm × 12cm
= 30cm²
The total area of the shapes then is 30cm² + 30 cm², giving us a total area of 60cm²
Answer:
40
Step-by-step explanation:
Ok, so basically let's start with a proportion.
x/32 = 11.25/9
Cross multiply:
x * 9 = 32 * 11.25
9x = 32 * 11.25
9x = 360
Solving for variable 'x'.
Divide each side by '9'.
x = 40
I don't know if this is the correct answer, but it was based on my math. I hope this helps!
Answer:
Part 1) The measure of arc EHL is 
Part 2) The measure of angle LVE is 
Step-by-step explanation:
step 1
Let
x-----> the measure of arc EHL
y----> the measure of arc EVL
we know that
The measurement of the outer angle is the semi-difference of the arcs it encompasses.
so

we have

substitute

------> equation A
Remember that
-----> equation B ( complete circle)
substitute equation A in equation B and solve for x



Find the value of y


therefore
The measure of arc EHL is 
The measure of arc EVL is 
step 2
Find the measure of angle LVE
we know that
The inscribed angle measures half that of the arc comprising
Let
x-----> the measure of arc EHL

we have

substitute
