3 years ago

(SAT PREP) Find the value of x.

Mathematics

1 answer:

PilotLPTM [1.2K]3 years ago

5 0

Answer:

x=120 is the answer it is hard to described without name

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Find all the zeroes of the equation(with simple steps).

uysha [10]

Answer-

The zeros are, $5,\ -5,\ 4i,\ -4i$

Solution-

$\Rightarrow -3x^4+27x^2+1200=0$

$\Rightarrow -3(x^2)^2+27(x^2)+1200=0$

Here,

a = -3, b = 27, c = 1200

So,

$x^2=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$=\dfrac{-27\pm \sqrt{-27^2-4\cdot (-3)\cdot 1200}}{2\cdot (-3)}$

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$=\dfrac{-27+123}{-6},\ \dfrac{-27- 123}{-6}$

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So,

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3 years ago

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salantis [7]

Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Harlamova29_29 [7]

Answer:

Point Form:

(0,-2)

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Step-by-step explanation:

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