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2 years ago

(SAT PREP) Find the value of x.

Mathematics

1 answer:

PilotLPTM [1.2K]2 years ago

5 0

Answer:

x=120 is the answer it is hard to described without name

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What is the value of x? Enter your answer in the box. __units

marshall27 [118]

I really don’t remember how to do these

7 0

2 years ago

Help i don’t know if my answers are correct and I need the other ones I didn’t answer to be answered to please help I need the c

qwelly [4]

Answer:
1) correct
2) correct
3) Not Congruent
4) Not Congruent
5) correct
6) Not Congruent
7) incorrect
8) SAS

Explanation:
7 is incorrect because the angle isn’t included in the sides

Hope this helps!

7 0

3 years ago

Find the zero(s) of each function algebraically. f(x) = 8x-16

vodomira [7]

the zero(s) of function $f(x)=8x-16$ is x=2

Step-by-step explanation:

We need to find the zero(s) of function algebraically.

We are given: $f(x)=8x-16$

To find the zeros we put the function equal to zero.

$8x-16=0\\Solving:\\8x=16\\x=\frac{16}{8}\\x=2$

So, the zero(s) of function $f(x)=8x-16$ is x=2

Keywords: zero(s) of function

Learn more about zero(s) of function at:

#learnwithBrainly

4 0

3 years ago

Can I get help finding the value of m and n

Marina86 [1]

9514 1404 393

Answer:

m = 35

n = 110

Step-by-step explanation:

Adjacent angles in a parallelogram are supplementary.

n° = 180° -70°

n = 110

Opposite angles in a parallelogram are congruent.

2m° = 70°

m = 35 . . . . . . divide by 2°

4 0

2 years ago

A manufacturer produces bolts of a fabric with a fixed width. A quantity q of this fabric (measured in yards) that is sold is a

BigorU [14]

Answer:

$R'(20) = 2000$

Step-by-step explanation:

We are given the following in the question:

Quantity, q

Selling price in dollars per yard, p

$q=f(p)$

Total revenue earned =

$R(p)=pf(p)$

f(20)=13000

This means that 13000 yards of fabric is sold when the selling price is 20 dollars per yard.

f′(20)=−550

This means that increasing the selling price by 1 dollar per yards there is a decrease in fabric sales by 550.

We have to find R'(20)

Differentiating the above expression, we have,

$R'(p) = \displaystyle\frac{d(R(p))}{dp} = \frac{d(pf(p))}{dp} = f(p) + pf'(p)$

Putting the values, we get,

$R'(p) = f(p) + pf'(p)\\\\R'(20) = f(20) + 20(f'(20))\\\\R'(20) = 13000 + 20(-550) = 2000$

7 0

3 years ago