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3 years ago

What is the PE of an object with a mass of 10 kg, and 2 meters up

Physics

2 answers:

Kipish [7]3 years ago

5 0

Answer:200 joules

Explanation:

Potential energy=mass×acceleration due to gravity×height

Potential energy=10×10×2

Potential energy=200 joules

Thepotemich [5.8K]3 years ago

4 0

Answer:

196.2 J

Explanation:

PE = mass x accel. due to gravity x height

= 10 kg x 9.81 m/s² x 2 m

= 196.2 J

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dedylja [7]

Hello!

This is a matter of superposition.
When the waves peak at the same time and place, they produce constructive interference, meaning the waves interact together in a positive way, to make a wave with Amplitude of both waves added together. When the peaks differ however, at the same time and place, then it is destructive interference and the waves essentially cancel each other out.

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3 years ago

A woman rides a carnival Ferris wheel at radius 20 m, completing 6.0 turns about its horizontal axis every minute. What are (a)

natta225 [31]

Answer:

Explanation:

Given

radius of ferris wheel is 20 m

It completes 6 turns in 1 min

i.e. 1 turn in 10 sec

Therefore its angular velocity is $\omega =\frac{2\pi }{10} rad/s$

(a)Period of motion is 10 s

Magnitude of centripetal acceleration is $\omega ^2r$

$=\left ( \frac{\pi }{5}\right )^2\times 20=7.89 m/s^2$

(b)Highest point will be 40 m

7 0

3 years ago

Children in a tree house lift a small dog in a basket 4.00 m up to their house. If it takes 187 J of work to do this, what is th

Vika [28.1K]

A=Fh
A - work
F - force
h - distance

F=mg
m - mass (god+basket)

so
A=mgh
187 = m*10*4
187=40m
m=187/40
m=4.675 kg
or 4kg and 675g

pretty small dog...

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3 years ago

Force F=2.0N i - 3.0N k acts on a pebble with position vectorr=0.50m j - 2.0m k relative to the origin. In unit vector notation,

klasskru [66]

Answer with Explanation:

We are given that

Force acts on a pebble= $2\hat{i}-3\hat{k}$ N

Position vector= $r=0.5\hat{j}-2\hat{k}$ m

a.We have to find the resulting torque on the pebble about origin.

Torque= $r\times F$

Substitute the values then we get

$Torque= (0.5j-2k)\times (2i-3k)$

Torque= $-k-1.5i-4j$ N-m

By using $i\times j=k,j\times k=i,k\times i=j,j\times i=-k,k\times j=-i,i\times k=-j,i\times i=j\times j=k\times k=0$

b. $r=2i-3k$

$r-r_1=(0.5j-2k)-(2i-3k)=-2i+0.5j+k$

Torque about point (2,0,-3)

$\tau=(-2i+0.5j+k)\times (2i-3k)$

$\tau=-6j-k-1.5i+2j=-1.5i-4j-k$ N-m

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3 years ago

PLZZ HELP How do the densities of various liquids and solids compare?

Genrish500 [490]

Answer:Density: The molecules of a liquid are packed relatively close together. Consequently, liquids are much denser than gases. The density of a liquid is typically about the same as the density of the solid state of the substance. ... Compression would force the atoms on adjacent molecules to occupy the same region of space.

Explanation:

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3 years ago