1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BlackZzzverrR [31]
3 years ago
15

Which of these is an example of a physical change? Question options: wood decaying iron melting paper burning steel rusting

Physics
1 answer:
marin [14]3 years ago
4 0
Im pretty sure burning paper

its either that or melting iron but im 90 percent sure its paper burning
You might be interested in
Carbon and hydrogen are examples of pure substances or
bogdanovich [222]
Carbon and hydrogen are also examples of elements
6 0
3 years ago
A series LRC circuit consists of a 12.0-mH inductor, a 15.0-µF capacitor, a resistor, and a 110-V (rms) ac voltage source. If th
finlep [7]

Answer:

61.85 ohm

Explanation:

L = 12 m H = 12 x 10^-3 H, C = 15 x 10^-6 F, Vrms = 110 V, R = 45 ohm

Let ω0 be the resonant frequency.

\omega _{0}=\frac{1}{\sqrt{LC}}

\omega _{0}=\frac{1}{\sqrt{12\times 10^{-3}\times 15\times 10^{-6}}}

ω0 = 2357 rad/s

ω = 2 x 2357 = 4714 rad/s

XL = ω L = 4714 x 12 x 10^-3 = 56.57 ohm

Xc = 1 / ω C = 1 / (4714 x 15 x 10^-6) = 14.14 ohm

Impedance, Z = \sqrt{R^{2}+\left ( XL - Xc \right )^{2}}

Z = \sqrt{45^{2}+\left ( 56.57-14.14 )^{2}} = 61.85 ohm

Thus, the impedance at double the resonant frequency is 61.85 ohm.

7 0
3 years ago
Consider a composite cube made of epoxy with fibers aligned along one axis of the cube (the fibers are parallel to four of the t
coldgirl [10]

The question is incomplete. The complete question is :

Consider a composite cube made of epoxy with fibers aligned along one axis of the cube (the fibers are parallel to four of the twelve cube edges). If the cube can only be loaded in axial tension such that the force is uniformly applied over - and is normal to - a cube face, what is the lowest possible positive length change the cube can experience under this tension? The applied tensile force is 102 KN. The unloaded cube edge length is 56 mm. The glass fibers have an elastic modulus of 200 GPa. The epoxy has an elastic modulus of 38 GPa. The cube is comprised of 18 vol% epoxy (the balancing vol % is glass fiber). Hint: The loading axis is intentionally unspecified. Answer Format: Lowest possible length increase (change of length) under tension.

Solution :

Given :

$E_{glass fibre}$ = 200 GPa

$V_{glass fibre} = 82\%$

$E_{epoxy}$ = 38 GPa

$V_{epoxy} = 82\%$

Edge length = 56 mm

Cube is loaded in axial tension such that the force is uniformly applied over a cube face.

$E_{\text{composite}}=\frac{E_{glass fibre} \times E_{epoxy}}{(E_{glass fibre .E_{epoxy}})+(E_{fibre}.V_{glass fibre})}$

$E_{composite} = \frac{200 \times 38}{(200 \times 0.18)+(38\times 0.82)}$

               $=113.16 $  GPa

Applied stress $=\frac{\text{applied load}}{\text{area}}$

                    $\sigma=\frac{102 \times 10^3 \ N}{56 \times 56 \times 10^{-6} \ m^2}$

                       = 32.5 MPa

By Hooke's law

$\sigma = E . \epsilon$

$\sigma = E. \frac{\Delta l}{l}$

$\Delta l = \frac{\sigma}{E}\times l$

Length change, $\Delta l =\frac{32.5 \times 10^6 \ Pa}{113.16 \times 10^9 \ Pa}\times 56 \times 10^{-2} \ m$

$\Delta l = \frac{32.5 \times 56}{113.16} \times 10^{-3} \ mm$

   = 0.016 mm

7 0
3 years ago
A celestial body has these properties:
vichka [17]
I think that would be the moon

"too small to clear objects that are in its orbital path" , which means that it probably not a planet.

hope this helps
4 0
3 years ago
Read 2 more answers
Warmup: The International Space Station is orbiting with a velocity of 7,667 m/s at an altitude of 408,000 m. The radius of Eart
poizon [28]

Answer:

<u>8.671 \mathrm{m} / \mathrm{s}^{2}</u> is the centripetal acceleration.

Explanation:

As per given values  

Radius of earth (r) = 6371000 m

The "international space station" is orbiting with a velocity (v) = 7667 m/s.

"Centripetal acceleration" is the acceleration is equal to "the square of the velocity" divided by "the radius of the circular path".

\text { Centripetal acceleration a }=\frac{V^{2}}{R}

V = velocity of the orbit

R = radius of the earth + height of the space station

R = 6,371,000 + 408,000

R = 6779000 m

The direction of the centripetal acceleration is always inwards along the radius vector of the circular motion.

a=\frac{7667^{2}}{6779000}

a=\frac{58782889}{6779000}

\mathrm{a}=8.671 \mathrm{m} / \mathrm{s}^{2}

\text { The International Space Station's centripetal acceleration } 8.671 \mathrm{m} / \mathrm{s}^{2}.

5 0
3 years ago
Other questions:
  • If you know a car is traveling 300 km in 3 hours, you can find its
    11·1 answer
  • What medium does sound travel through the quickest and why
    11·1 answer
  • A runner starts at point A runs around a 1 mile track and finishes the run back at point A. Which of the following statement is
    15·1 answer
  • The space shuttle usually orbited Earth at altitudes of around 300.0 km. 1) Determine the time for one orbit of the shuttle abou
    8·1 answer
  • A tetrahedron has an equilateral triangle base with 25.0-cm-long edges and three equilateral triangle sides. The base is paralle
    12·1 answer
  • A hole of radius r is bored through the center of a sphere of radius r. Find the volume v of the remaining portion of the sphere
    15·2 answers
  • 4. A sodium ion has a +1 relative atomic charge which indicates it has one more proton than electron.
    8·1 answer
  • WILL GIVE BRAINLIST: Does an objects weight affect how fast it falls?
    10·1 answer
  • A 2.00 kg cat is in a 97.00 kg elevator. What force on the elevator cable would be needed to lower the cat/elevator pair with an
    6·1 answer
  • Energy released by the sun results from the process where atomic nuclei
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!