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Dahasolnce [82]
3 years ago
10

An object undergoing simple harmonic motion completes one cycle of motion in 1.7 seconds. Determine the angular frequency (rad/s

) of the motion.
Physics
1 answer:
Aliun [14]3 years ago
4 0

Answer:

3.69 rad/s

Explanation:

From the question given above, the following data were obtained:

Period (T) = 1.7 s

Angular frequency (ω) =?

Thus, we can obtain the angular frequency (ω) by applying the following formula:

ω = 2π/T

Period (T) = 1.7 s

Pi (π) = 3.14

Angular frequency (ω) =?

ω = 2π/T

ω = 2 × 3.14 / 1.7

ω = 6.28 / 1.7

ω = 3.69 rad/s

Thus, the angular frequency of the motion is 3.69 rad/s

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Answer:

The object starts away from the origin and then moves toward the origin at a constant velocity. Next, it stops for one second. Finally, it moves away from the origin at a greater constant velocity.

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a car advertisement claims their car can go from a stopped position to move 60 miles per hour in 5 seconds the advertisement is
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What do you want us to anwser
7 0
3 years ago
A- 1000 m/s2<br> Xi-0m<br> Xf-0.75m<br> Vf-?
sleet_krkn [62]

Answer:

The final velocity of the object is,  v_{f} = 27 m/s    

Explanation:

Given,

The acceleration of the object, a = 1000 m/s²

The initial displacement of the object, x_{i} = 0 m

The final displacement of the object,  x_{f} = 0.75 m

The initial velocity of the object will be, v_{i} = o m/s

The final velocity of the object, v_{f} = ?

The average velocity of the object,

                                    v = ( x_{f} - x_{i} )/ t

                                      = 0.75 / t

The acceleration is given by the relation

                                     a = v / t

                                   1000 m/s² = 0.75 / t²

                                            t² = 7.5 x 10⁻⁴

                                            t = 0.027 s

Using the I equation of motion,

                                  v_{f} = u + at

Substituting the values

                                   v_{f} = 0 + 1000 x 0.027

                                                           = 27 m/s

Hence, the final velocity of the object is,  v_{f} = 27 m/s          

8 0
4 years ago
The fluid pressure 10 ft underwater is _____ the fluid pressure 5 ft underwater. A.less than or greater than, depending on what
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5 0
3 years ago
A car with a total mass of 1800 kg (including passengers) is driving down a washboard road with bumps spaced 4.9 m apart. The ri
Drupady [299]

Answer:

k = 9.6 x 10^5 N/m or 9.6 kN/m

Explanation:

First, we need to use the expression to calculate the spring constant which is:

w² = k/m

Solving for k:

k = w²*m

To get the angular velocity:

w = 2πf

The problem is giving the linear velocity of the car which is 5.7 m/s. With this we can calculate the frequency of the car:

f = V/x

f = 5.7 / 4.9 = 1.16 Hz

Now the angular velocity:

w = 2π*1.16

w = 7.29 rad/s

Finally, solving for k:

k = (7.29)² * 1800

k = 95,659.38 N/m

In two significant figures it'll ve 9.6 kN/m

5 0
3 years ago
Read 2 more answers
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