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Dahasolnce [82]
3 years ago
10

An object undergoing simple harmonic motion completes one cycle of motion in 1.7 seconds. Determine the angular frequency (rad/s

) of the motion.
Physics
1 answer:
Aliun [14]3 years ago
4 0

Answer:

3.69 rad/s

Explanation:

From the question given above, the following data were obtained:

Period (T) = 1.7 s

Angular frequency (ω) =?

Thus, we can obtain the angular frequency (ω) by applying the following formula:

ω = 2π/T

Period (T) = 1.7 s

Pi (π) = 3.14

Angular frequency (ω) =?

ω = 2π/T

ω = 2 × 3.14 / 1.7

ω = 6.28 / 1.7

ω = 3.69 rad/s

Thus, the angular frequency of the motion is 3.69 rad/s

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The terminal velocity of the gold sphere is given by v = 2gr²(ρ - σ)/9η where

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