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3 years ago

I need a lot of questions answered, I'm sorry!

Mathematics

1 answer:

Rashid [163]3 years ago

4 0

1.3272
2.23.1
3.384
4.13.5
9.2.4
Sorry I dont know the rest but i hope i helped.

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What principle will amount to $6000 if invested at 5.5% compounded monthly for 10 years?

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Answer:In 10 years, you will have $10,386.46

Step-by-step explanation:

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2 years ago

What is Three less than seven

irina1246 [14]

Answer: 4

Step-by-step explanation:

7-3=4

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3 years ago

Read 2 more answers

Stephen’s lunch bill is currently at $8.33. Stephen orders a fruit salad for take-out, and wants to leave $2.25 as a tip for his

KatRina [158]

Answer:

$4.42

Step-by-step explanation:

by combining $8.33 and $2.25 you get a combined total of $10.58 and if you subtract that from $15 you get $4.42 as the amount of money remaining.

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3 years ago

In a manufacturing process a random sample of 9 bolts manufactured has a mean length of 3 inches with a standard deviation of .3

Serggg [28]

Answer:

The correct option is (C) (2.769, 3.231).

Step-by-step explanation:

The confidence interval for mean when the standard deviation is not known is:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\frac{s}{\sqrt{n}}$

Given:

$\bar x = 3\\s=0.3\\n=9\\\alpha =1-0.95=0.05$

Compute the critical value as follows:

$t_{\alpha/2, (n-1)}=t_{0.05/2, (9-1)}=t_{0.025, 8}=2.31$

**Use a <em>t</em>-table.

The 95% confidence interval for true mean length of the bolt is:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\frac{s}{\sqrt{n}}\\=3\pm 2.31\times \frac{0.30}{\sqrt{9}}\\ =3\pm 0.231\\=(2.769, 3.231)$

Thus, the 95% confidence interval for true mean length of the bolt is (2.769, 3.231).

The correct option is (C).

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3 years ago

According to a survey conducted by Deloitte in 2017, 0.4702 of U.S. smartphone owners have made an effort to limit their phone u

musickatia [10]

Answer: 0.628

Step-by-step explanation:

Probability of U.S. smartphone owners have made an effort to limit their phone use in the past : p = 0.4702

Sample size : n= 54

Mean : $\mu =(54)(0.4702)=25.39$

Standard deviation:

$\sigma=\sqrt{(54)(0.4702)}=\sqrt{25.39}\\\\\approx5.039$

The probability that between 22 and 29 (inclusively) will have attempted to limit their cell phone use in the past will be :

$P(22\leq x\leq29)=P(21$

Hence, the required probability = 0.628

5 0

3 years ago