$\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{10})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{-14}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-14}-\stackrel{y1}{10}}}{\underset{run} {\underset{x_2}{10}-\underset{x_1}{(-2)}}}\implies \cfrac{-24}{10+2}\implies \cfrac{-24}{12}\implies -2$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{-2}[x-\stackrel{x_1}{(-2)}]\implies y-10=-2(x+2) \\\\\\ y-10=-2x-4\implies y=-2x+6$

5 0

3 years ago

The answer to this difficult question in my math book that I have to solve. Can you help me?

s2008m [1.1K]

A half hour is 30 minutes. So you would need to divide 30 by 5 and you get six. Multiple 6 degrees Fahrenheit by 6 and you get 36 degrees. The solution cooled 36 degrees in half an hour.

Hope this helps!

4 0

3 years ago

How do i Solve: 3x2−6x−12=0 ?

MrMuchimi

Answer:

1 + root 5, 1 - root 5

Step-by-step explanation:

I assume you mean 3x^2-6x-12=0.

First, note that you can divide both sides by 3. You get:

x^2-2x-4=0

Use the quadratic equation.

$x=\frac{2\pm\sqrt{4+16}}{2}=\frac{2\pm2\sqrt{5}}{2}=1\pm\sqrt{5}$

Therefore, x=1 + root 5, 1 - root 5

4 0

3 years ago

7x/2+5=8<br><br> solve for x

ANEK [815]

Answer:

X= 6/7

Step-by-step explanation:

4 0

3 years ago

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