How can i prove that nascent oxygen more reactive than normal oxygen ?

If the mass of a certain block is 500g, what is the weight of the block?

Dafna11 [192]

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Solution,

Mass=500g =500/1000=0.5 kg

gravity(g)=9.8m/s^2

Now,

Weight= m*g

 = 0.5*9.8

 =4.9 N

So the weight of the block is 4.9 Newton

hope it helps...

Good luck on your assignment

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5 0

3 years ago

SOME ONE HEEEEELLLLPPPPPPPP PLEAAASEEE

stellarik [79]

Answer:

look up chemical board it will help you

Explanation:

6 0

3 years ago

What is the molarity of a solution that contains 0.400 mol HCI in 9.79 L solutions

USPshnik [31]

Molarity's formula is known as: Molarity(M)=moles of solute/liters solution.

In this case we are already given moles and liters so you just have to plug the numbers into the equation.

0.400 mol HCL/9.79L solution=0.040858M

If you were to use scientific notation, the answer will be: 4.1*10^-2, but otherwise, you can just use the decimals above and round appropriately as you see fit.

6 0

3 years ago

Is this an aromatic hydrocarbon? Why or why not?

swat32

The correct answer is D

3 0

3 years ago

Read 2 more answers

Use the following equation to answer question 1-4. Make sure you balance first.

worty [1.4K]

<h3>Answer:</h3>

5.2 mol H₂O

<h3>General Formulas and Concepts:</h3>

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Stoichiometry

Using Dimensional Analysis

<h3>Explanation:</h3>

Step 1: Define

[RxN - Balanced] 6HCl + Fe₂O₃ → 2FeCl₃ + 3H₂O

[Given] 10.4 mol HCl

Step 2: Identify Conversions

[RxN] 6 mol HCl = 3 mol H₂O

Step 3: Stoichiometry

Set up: $\displaystyle 10.4 \ mol \ HCl(\frac{3 \ mol \ H_2O}{6 \ mol \ HCl})$
Multiply/Divide: $\displaystyle 5.2 \ mol \ H_2O$

4 0

3 years ago