Answer:1:1
There is a 1:1 molar ratio between magnesium and magnesium chloride. Magnesium has a molar mass of 24.31g/mol.
Explanation:
If you begin with 25.0 g of magnesium, how many moles of magnesium oxide will ... g C9H8O4. Now calculate percent yield. % yield = actual theoretical. × 100 =.
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Answer:
<em>The correct option is the structure in the option D. </em>
Explanation:
Ammonia contains a single nitrogen atom bonded to three hydrogen atoms.
The structure present in option A shows a single nitrogen atom bonded with a single hydrogen atom hence it is not correct.
The structure in option B shows a nitrogen atom bonded to four hydrogen atoms hence it is also not correct.
The structure in option C shows a nitrogen atom bonded to two hydrogen atoms hence it is also not correct.
The structure in option D shows a nitrogen atom bonded to three hydrogen atoms which is the correct structure of ammonia (NH3).
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Answer:
4.16x10⁻³m
Explanation:
Molality is defined as the ratio between moles of a solute, in this case glucose, and kg of solvent.
As there are 100g of solvent, <em>the kg are 0.1. </em>Thus, we only need to calculate from the mass of glucose its moles to solve the molality of the solution.
<em>Moles glucose:</em>
There are 75mg = 0.075g of glucose. To conver mass to moles it is necessary molar mass.
Molar mass glucose:
6C = 12.01g/mol*6 = 72.06g/mol
12H = 12*1.008g/mol = 12.10g/mol
6O = 6*16g/mol = 96g/mol
72.06 + 12.10 + 96 = 180.16g/mol
Moles of 0.075g of glucose:
0.075g * (1 mol / 180.16g) =
4.16x10⁻⁴ moles of glucose
<em>Molality of the solution:</em>
4.16x10⁻⁴ moles of glucose / 0.1kg of solvent =
<h3>4.16x10⁻³m</h3>
