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fomenos
4 years ago
10

Quais sao os princiais instrumentos da meteorologia?

Chemistry
1 answer:
denpristay [2]4 years ago
4 0

Answer:

Thermometer - air temperature,

Barometer - air pressure,

Hygrometer - humidity,

Anemometer - wind speed,

Ceilometer - Cloud cover,

Rain/Snow gauge - precipitation

Pyranometer/ Pyrheliometer - net radiation

Explanation:

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Sodium chloride reacts with copper sulfate to produce sodium sulfate and copper chloride. mc011-1.jpg This equation represents a
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This is a double replacement because both Copper and Sodium reacted with each other compounds , hence "double"
7 0
3 years ago
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A. True <br> b. False a chemical species is either an acid or a base, it cannot function as both
ivann1987 [24]
False They can function as both. An example is Aluminium Oxide. These kind of substances are called "Amphoteric", they can behave as both acids and bases.
3 0
3 years ago
Will an object with a density of 0.999 sink or float
Semmy [17]

The density of an object determines whether it will float or sink in another substance. An object will float if it is less dense than the liquid it is placed in. An object will sink if it is more dense than the liquid it is placed in.

7 0
3 years ago
3. Suppose you had titrated your vinegar sample with barium hydroxide instead of sodium hydroxide:
charle [14.2K]

Answer:

39.6 mL

Explanation:

Step 1: Write the balanced neutralization reaction

Ba(OH)₂(aq) + 2 CH₃COOH(aq) ⟶ Ba(CH₃COO)₂(aq) + 2 H₂O(l)

Step 2: Calculate the moles corresponding to 2.78 g of CH₃COOH

The molar mass of CH₃COOH is 60.05 g/mol.

2.78 g × 1 mol/60.05 g = 0.0463 mol

Step 3: Calculate the moles of Ba(OH)₂ needed to react with 0.0463 moles of CH₃COOH

The molar ratio of Ba(OH)₂ to CH₃COOH is 1:2. The moles of Ba(OH)₂ needed are 1/2 × 0.0463 mol = 0.0232 mol.

Step 4: Calculate the volume of 0.586 M solution that contains 0.0232 moles of Ba(OH)₂

0.0232 mol × 1 L/0.586 mol = 0.0396 L = 39.6 mL

6 0
3 years ago
NEEED!! HELP!!!
sweet [91]

C

high specific heat capacity means water stores a lot of heat

when it is hot outside, water stores the heat, causing it to not be as hot as it could be without water

when it is cold outside, the heat from inside the water is transfered outside so that the temperature isn't as cold as it could be

so A and B are wrong (opposite)

In the case of internal temperature, the high specific heat of water should prevent variation, but I'm not too sure

4 0
3 years ago
Read 2 more answers
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