Answer:
it's a two step elimination reaction
Explanation:
it follows a carbocationic pathway. When carbocation is stable, the equation is favourable, that is, double bond is formed by expelling hydrogen atom.
Answer:
condensation - B, melting - C, sublimation - A, freezing - D
Explanation:
condensation : condenstaion is process of change of phase of a substance from gaseous to liquid
evaporation : evaporation is process of change of phase of a substance from liquid to gaseous.
melting : melting is process of change of phase of a substance from solid to liquid.
freezing : freezing is process of change of phase of a substance from liquid to solid.
sublimation : sublimation is process of change of phase of a substance from solid to gaseous.
Mars is the inner planet with the most moons. Earth has one moon, Mars has two and Mercury and Venus have none.
Answer:
The change in internal energy is - 1.19 kJ
Explanation:
<u>Step 1:</u> Data given
Heat released = 3.5 kJ
Volume calorimeter = 0.200 L
Heat release results in a 7.32 °C
Temperature rise for the next experiment = 2.49 °C
<u>Step 2:</u> Calculate Ccalorimeter
Qcal = ccal * ΔT ⇒ 3.50 kJ = Ccal *7.32 °C
Ccal = 3.50 kJ /7.32 °C = 0.478 kJ/°C
<u>Step 3:</u> Calculate energy released
Qcal = 0.478 kJ/°C *2.49 °C = 1.19 kJ
<u>Step 4:</u> Calculate change in internal energy
ΔU = Q + W W = 0 (no expansion)
Qreac = -Qcal = - 1.19 kJ
ΔU = - 1.19 kJ
The change in internal energy is - 1.19 kJ
Given the data from the question, the final temperature is 200 K, while pressure remains constant.
<h3>Basic concepts </h3>
To obtain the correct answer to the question, we shall consider two conditions:
- Case 1 (temperature is constant)
- Case 2 (pressure is constant)
<h3>Case 1 (Temperature is constant) </h3>
We shall determine the new pressure by using the combined gas equation (P₁V₁ / T₁ = P₂V₂ / T₂) as illustrated below:
- Initial volume (V₁) = 3 L
- Initial pressure (P₁) = 1 atm
- Temperature = constant
- New Volume (V₂) = 2 L
- New pressure (P₂) =?
P₁V₁ / T₁ = P₂V₂ / T₂
Since temperature is constant, we have:
P₁V₁ = P₂V₂
3 × 1 = P₂ × 2
3 = P₂ × 2
Divide both side by 2
P₂ = 3 / 2
P₂ = 1.5 atm
<h3>Case 2 ( pressure is constant) </h3>
We shall determine the new temperature by using the combined gas equation (P₁V₁ / T₁ = P₂V₂ / T₂) as illustrated below:
- Initial volume (V₁) = 3 L
- Initial pressure (T₁) = 300 K
- Pressure = constant
- New Volume (V₂) = 2 L
- New pressure (T₂) =?
P₁V₁ / T₁ = P₂V₂ / T₂
Since pressure is constant, we have:
V₁ / T₁ = V₂ / T₂
3 / 300 = 2 / T₂
1 / 100 = 2 / T₂
Cross multiply
T₂ = 100 × 2
T₂ = 200 K
SUMMARY
- when the temperature is constant, the new pressure is 1.5 atm
- When the pressure is constant, the new temperature is 200 K
From the calculations made above, we can conclude that the correct answer is:
The final temperature is 200 K, while pressure remains constant.
Learn more about gas laws:
brainly.com/question/6844441