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Dmitrij [34]
2 years ago
6

Use the following equation to answer question 1-4. Make sure you balance first.

Chemistry
1 answer:
worty [1.4K]2 years ago
4 0
<h3>Answer:</h3>

5.2 mol H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 6HCl + Fe₂O₃ → 2FeCl₃ + 3H₂O

[Given] 10.4 mol HCl

<u>Step 2: Identify Conversions</u>

[RxN] 6 mol HCl = 3 mol H₂O

<u>Step 3: Stoichiometry</u>

  1. Set up:                             \displaystyle 10.4 \ mol \ HCl(\frac{3 \ mol \ H_2O}{6 \ mol \ HCl})
  2. Multiply/Divide:               \displaystyle 5.2 \ mol \ H_2O
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Sidana [21]

The solution for this problem is:

The information given lacks but nevertheless the answer is:
So, the total heat free by dissolving the solute was 1386 + 32 = 1417 J
Then, dissolving of the solute will have released -1417 J. So, per gram of Al2 (SO4)3 dissolved: 
-1417 J / 25 g = -56.7 J/g 


Translating that to a per mole: -56.7 J/g X 342 g/mol = -1.94X10^4 J/mol = -19 kJ/mol = this would be Delta Hsoln

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Copper sulfate is made of one copper (Cu) atom, one sulfur (S) atom, and four oxygen (O) atoms. Write the chemical formula corre
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3 years ago
A compound contains 25.93% N and the rest is oxygen. What is the empirical formula for the compound?
Mnenie [13.5K]

Answer: NO2

Explanation:

                                  N                                O

Divide each by its    25.93                       74.07

mass number              14                             16

                                     2                              4

Divide both by the       2                               2

smaller (i.e. 2)               1                                2

Therefore, the empirical formula = NO2

                                     

5 0
3 years ago
consider an exceptionally weak acid, HA, with Ka= 1 x 10-20. you make 0.1M solution of the salt NA. what is the pH.
iogann1982 [59]

Answer:

pH=10.5

Explanation:

Hello,

In this case, the dissociation of the given weak acid is:

HA\rightleftharpoons H^++A^-

Therefore, the law of mass action for it turns out:

Ka=\frac{[H^+][A^-]}{[HA]}

That in terms of the change x due to the reaction extent is:

1x10^{-23}=\frac{x*x}{0.1-x}

Thus, by solving with the quadratic equation or solver, we obtain:

x=31.6x10^{-12}M

Which clearly matches with the hydrogen concentration in the solution, therefore, the pH is:

pH=-log(-31.6x10^{-12})\\pH=10.5

Regards.

5 0
3 years ago
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