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Ratling [72]
3 years ago
10

What element is found in large amounts in muscle tissue and nerve tissue?

Chemistry
1 answer:
ra1l [238]3 years ago
7 0
Calcium maybe... Because it has protein lol
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The circles in the model represent atmospheric layers. Make each description with the correct name of each layer.
Masja [62]

Answer:

The bottom is troposhere the next is sratoshere,mesosphere,thermosphere then exoshere

Explanation:

6 0
3 years ago
How many molecules are there in 5H20?<br> A.5<br> B.7<br> C.10<br> D.11
Ad libitum [116K]

Answer:

the answers B which is 7

5 0
2 years ago
What is the number assigned to an element on the Periodic Table?
spayn [35]

Answer:

Element Atomic Number One number you will find on all periodic tables is the atomic number for each element.

Explanation:

<em>hope it helps :))</em>

6 0
2 years ago
The temperature of a 95.4 g piece of Cu increases from 25.0 °C to 48.0 °C when the Cu absorbs 849 J of heat. What is the specifc
melisa1 [442]
<h3>Answer:</h3>

0.387 J/g°C

<h3>Explanation:</h3>
  • To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
  • Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
  • That is, Q = mcΔT

in our question we are given;

Mass of copper, m as 95.4 g

Initial temperature = 25 °C

Final temperature = 48 °C

Thus, change in temperature, ΔT = 23°C

Quantity of heat absorbed, Q as 849 J

We are required to calculate the specific heat capacity of copper

Rearranging the formula we get

c = Q ÷ mΔT

Therefore,

Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)

                                        = 0.3869 J/g°C

                                        = 0.387 J/g°C

Therefore, the specific heat capacity of copper is 0.387 J/g°C

3 0
3 years ago
Which of the
saul85 [17]

Answer:

During chemical reactions, matter is neither

created nor destroyed; it just changes form.

Explanation:

6 0
3 years ago
Read 2 more answers
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