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slava [35]
3 years ago
7

Write the quadratic function in vertex form. y = x2 + 18x + 71

Mathematics
2 answers:
il63 [147K]3 years ago
6 0
X=67
___
20
??? Is that what you needed idk lol
Kisachek [45]3 years ago
4 0
It is going to look like y=(x+9)2+k for some kto find k replace x by −9 in the original expression and see what you get because y=(−9+9)2+k=0+k=k
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What is the value of x in the situation 5 1/6x + 2 1/4 =10
ASHA 777 [7]

Answer:

x=5/57

Step-by-step explanation:

(5/6x)+(1/2)=10

x=5/57

6 0
3 years ago
At the museum, the O'Rourke family bought 3 adult tickets and 2 children tickets for $23.50. The Patel family bought 2 adult tic
Tresset [83]
6.25 for each kids ticket and 11.75 for each adult ticket
4 0
2 years ago
What is the third angle of a right triangle if one of the angles measures 51.
Elodia [21]

Answer:

39

Step-by-step explanation:

The short answer is 39.

Every triangle has 180 degrees. There are no exceptions to this rule.

Since a triangle has 3 angles, all three together must add up to 180o

A right angle = 90 degrees always.

You are given 51 degrees as your second angle

The third one is x

x + 51 + 90 = 180                   Total of three angles must be 180

x + 141 = 180                           The left has been added to give 141

x = 180 - 141                            Subtract 141 from both sides

x = 39                                     The third angle = 39    

3 0
3 years ago
Please explain the answer​
Phantasy [73]

Answer:

  yes

Step-by-step explanation:

The side lengths satisfy the Pythagorean theorem, so the triangle is a right triangle.

  7.5² +10² = 12.5²

  56.25 +100 = 156.25

_____

You may recognize that the ratios of side lengths are ...

  7.5 : 10 : 12.5 = 3 : 4 : 5

A 3-4-5 triangle is a well-known right triangle, as this is the smallest set of integers that satisfy the Pythagorean theorem. They also happen to be consecutive integers, so form an arithmetic sequence. Any arithmetic sequence that satisfies the Pythagorean theorem will have these ratios.

_____

If you're familiar with trigonometry, you know the law of cosines tells you ...

  c² = a² + b² - 2ab·cos(θ) . . . . where θ is the angle between sides a and b. This reduces to the Pythagorean theorem when θ=90°, which makes cos(θ)=0. If the sides do not satisfy the Pythagorean theorem, cos(θ)≠0 and the triangle is not a right triangle.

7 0
3 years ago
Sin α = 21/29, α lies in quadrant II, and cos β = 15/17, β lies in quadrant I Find sin (α - β).
Sever21 [200]
\sin(\alpha-\beta)=\sin\alpha\cos\beta-\cos\alpha\sin\beta

\sin\alpha=\dfrac{21}{29}\implies \cos^2\alpha=1-\sin^2\alpha=\dfrac{400}{841}

Since \alpha lies in quadrant II, we have \cos\alpha, so

\cos\alpha=-\sqrt{\dfrac{400}{841}}=-\dfrac{20}{29}

\cos\beta=\dfrac{15}{17}\implies\sin^2\beta=1-\cos^2\beta=\dfrac{64}{289}

\beta lies in quadrant I, so \sin\beta>0 and

\sin\beta=\sqrt{\dfrac{64}{289}}=\dfrac8{17}

So

\sin(\alpha-\beta)=\dfrac{21}{29}\dfrac{15}{17}-\left(-\dfrac{20}{29}\right)\dfrac8{17}=\dfrac{475}{493}
8 0
3 years ago
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