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drek231 [11]
3 years ago
14

How much time does it take for tweety’s bird cage to hit the ground after it was dropped if it reached a velocity of 22 meters p

er second right before impact?
Physics
1 answer:
guajiro [1.7K]3 years ago
7 0
It matters on the weight

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What is located between the galaxies
nekit [7.7K]
Hey there,
The answer is voids, it is probably nearly empty.

Hope this helps :))

~Top
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3 years ago
What should you do to change a value in SI units in U.S customary units
AveGali [126]
Use a conversion factor
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3 years ago
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A typical atom has a diameter of about 1.32 x 10-10 m. (a) what is this in inches (b) approximately how many atoms arethere alon
JulijaS [17]

Answer:

A ) 5.197 \times 10 ^{-9} inches

b) There are approximately 100,000,000 atoms on the 1.32 cm lines

Explanation:

To ensure the accuracy of our answer, we will have to make sure we work in the appropriate units.

A

To convert    1.32 \times 10^{-10}   m to inches, we can use this factor.

1 m = 39.3701 inches

Therefore 1.32 \times 10^{-10}   m =  

B

To find the number of atoms on a 1.32 cm line, we will first of all need to convert 1.32 cm to meters.

1.32 cm = 0.0132 metres (divided 1.32 by 100 to convert to metres)

Assuming all the atoms are arranged side by side, with their edges touching on the 0.0132m line, the number of atoms present will be

0.0132/1.32\times 10^{-10} = 100,000,000 atoms

5 0
3 years ago
Two objects, m1 = 0.6 kg and m2 = 4.4 kg undergo a one-dimensional head-on collision
Sidana [21]

a) The velocity after the collision.is 11.456 m/s.

b) The kinetic energy lost due to the collision is 44.564 J.

<h3>What is conservation of momentum principle?</h3>

When two bodies of different masses move together each other and have head on collision, they travel to same or different direction after collision.

The external force is not acting here, so the initial momentum is equal to the final momentum. For inelastic collision, final velocity is the common velocity for both the bodies.

m₁u₁ +m₂u₂ =(m₁ +m₂) v

Given are the two objects, m1 = 0.6 kg and m2 = 4.4 kg undergo a one-dimensional head-on collision. Their initial velocities along the one-dimension path are vi1 = 32.4 m/s [right] and vi2 = 8.6 m/s [left].

(a) Substitute the values, then the final velocity will be

0.6 x32.4 +4.4 x 8.6 = (0.6+4.4)v

v = 11.456 m/s

Thus, the velocity after collision is 11.456 m/s.

(b) Kinetic energy lost due to collision will be the difference between the kinetic energy before and after collision.

= [1/2m₁u₁² +1/2m₂u₂² ] - [1/2(m₁ +m₂) v²]

Substitute the value, we have

= [1/2 x 0.6 x32.4² + 1/2 x4.4 x 8.6²] - [1/2 x(0.6+4.4)11.456²]

= 44.564 J

Thus, the kinetic energy lost due to the collision is 44.564 J.

Learn more about conservation of momentum principle

brainly.com/question/14033058

#SPJ2

4 0
2 years ago
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Which of the following is not a function of PACs?
Katena32 [7]

Answer:

i think D

hope this helps

let me know if i'm wrong i will change the answer

Explanation:

5 0
3 years ago
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