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statuscvo [17]
2 years ago
9

Why do electric charges that move through a magnetic field produce an electric current? A. The magnetic field exerts a force on

only the negative charges in the wire. B. The magnetic field pushes negative charges and positive charges in opposite directions. C. The magnetic field pushes negative charges and positive charges in the same direction. D. The magnetic field exerts a force on only the positive charges in the wire.​
Physics
2 answers:
Alex Ar [27]2 years ago
4 0

Answer: B

Explanation: a p e x :)

marshall27 [118]2 years ago
3 0

Answer:

B. The magnetic field pushes negative charges and positive charges in opposite directions.

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Is it possible that a speed of 254 and a speed of 100 could be the same speed?
EastWind [94]
Not if both speeds are in the same units.

However, if the 254 is 'centimeters per time' and the 100 is 'inches per time',
then the speeds are equal.
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3 years ago
It has been suggested that rotating cylinders several miles in length and several miles in diameter be placed in space and used
stepladder [879]

Answer:

the required revolution per hour is 28.6849

Explanation:

Given the data in the question;

we know that the expression for the linear acceleration in terms of angular velocity is;

a_{c} = rω²

ω² = a_{c} / r

ω = √( a_{c} / r )

where r is the radius of the cylinder

ω is the angular velocity

given that; the centripetal acceleration equal to the acceleration of gravity a a_{c}  = g = 9.8 m/s²

so, given that, diameter = 4.86 miles = 4.86 × 1609 = 7819.74 m

Radius r = Diameter / 2 = 7819.74 m / 2 = 3909.87 m

so we substitute

ω = √( 9.8 m/s² / 3909.87 m )

ω = √0.002506477 s²  

ω = 0.0500647 ≈ 0.05 rad/s  

we know that; 1 rad/s = 9.5493 revolution per minute

ω = 0.05 × 9.5493 RPM

ω = 0.478082 RPM  

1 rpm = 60 rph  

so  

ω = 0.478082 × 60

ω = 28.6849  revolutions per hour  

Therefore, the required revolution per hour is 28.6849

7 0
3 years ago
What led astronomers to believe in the existence of dark matter?
Tju [1.3M]
It’s either C or D. let me know but I would do C!
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3 years ago
Sound wave W has amplitude ‘A' and frequency ‘f'. Sound wave X is louder and lower in pitch than sound wave W. What can be said
ra1l [238]

Answer:

Sound wave X amplitude is greater than 'A' and its frequency is lesser than

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Explanation:

The pitch of a sound is dictated by the frequency of the sound wave, while the loudness is dictated by the amplitude.

A high pitch sound corresponds to a high frequency and a low pitch sound corresponds to a low frequency.

The larger the amplitude of the waves, the louder the sound and vice-versa.

From the question,

Sound wave W has amplitude ‘A' and frequency 'f' and

Sound wave X is louder and lower in pitch than sound wave W.

Since sound wave X is louder, this means its amplitude is greater than 'A'.

Also, since sound wave X is lower in pitch, this means its frequency is lesser than 'f'.

7 0
3 years ago
When the number of electrons striking the anode of an x-ray tube is increased, the ____ of the emitted X-Ray increases.
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When the number of electrons striking the anode of an X-ray tube is increased, the density of the emitted x-ray increases
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