Answer:
Hey! Your answer -:
P.E = Mgh
= 35*9.8*1.5
= 514.5
So, pe of ur dog is 514.5
Hope it helps!
Answer:
a) Magnitude of maximum emf induced = 0.0714 V = 71.4 mv
b) Maximum current through the bulb = 0.00793 A = 7.93 mA
Explanation:
a) The induced emf from Faraday's law of electromagnetic induction is related to angular velocity through
E = NABw sin wt
The maximum emf occurs when (sin wt) = 1
Maximum Emf = NABw
N = 1
A = 4 cm² = 0.0004 m²
B = 6 T
w = (284/60) × 2π = 29.75 rad/s
E(max) = 1×0.0004×6×29.75 = 0.0714 V = 71.4 mV
Note that: since we're after only the magnitude of the induced emf, the minus sign that indicates that the induced emf is 8n the direction opposite to the change in magnetic flux, is ignored for this question.
b) Maximum current through the bulb
E(max) = I(max) × R
R = 9 ohms
E(max) = 0.0714 V
I(max) = ?
0.0714 = I(max) × 9
I(max) = (0.0714/9) = 0.00793 A = 7.93 mA
Hope this Helps!!
<span>We know that the relation between pressure, volume and temperature is constant for ideal gases, so then
P1*V1/T1 = P2*V2/T2
As the volume is held constant, we will have:
P1/T1 = P2/T2
As the pressure is doubled and the temperature in kelvins is 211.15 K, then:
P1/211.15 = 2*P1/T2
T2 = 2*211.15 = 422.3 K
T2 = 422.3 - 273.15 = 149.15
So the final temperature reaches 149.15 ÂşC</span>
Let you be at point A while your friend be at point B,
while you are still having lunch,
you friend travels= 27/60*75miles/h=33.75miles
Remaining Distance= 135miles-33.75miles=101.25miles
Take note here is the tricky part, for the remaining distance both you and your friend are driving towards each other,
So first,
Total speed =Adding both ur friend and ur speed= 60+75=135miles/h
Time taken to meet= 101.25miles/135miles/h=0.75h
Total hours ur friend drives= 0.75h+27/60h=1.2h
total distance ur friend drove= 1.2h * 75miles/h= 90km
for the part how far u travelled,
simply take 135miles -90miles=45miles
Answer:
the height of the cliff is equal to 108.241 m
Explanation:
given,
initial speed of the stone horizontally = 9 m/s
vertical speed of the stone = 0 m/s
time taken of the trajectory = 4.7 s
using equation of motion
s = 108.241 m
hence, the height of the cliff is equal to 108.241 m