Answer:
If 20 is 5% multiplying it by 20 would give us 100%, so 20*20=400. There are 400 sixth-grade students in total.
Answer:
f(x)=3x-2
g(x)=x^2
(g o f)(3)=?
(g o f)(3)=g(f(3))
x=3→f(3)=3(3)-2
f(3)=9-2
f(3)=7
(g o f)(3)=g(f(3))=g(7)
x=7→g(7)=7^2
g(7)=49
Answer: (g o f)(3)=49
OR,if you like this answer can also work
For this case, the first thing we must do is the composition of functions.
We have:
f (x) = 3x-2
g (x) = x ^ 2
(gOf) (x) = (3x-2) ^ 2
We now evaluate the function:
(gOf) (3) = (3 * (3) -2) ^ 2
(gOf) (3) = (9-2) ^ 2
(gOf) (3) = (7) ^ 2
(gOf) (3) = 49
Answer:
(gOf) (3) = 49
Both are same
Hope it is helpful to you
Answer:
(- 5, 0), (3, 4)
Step-by-step explanation:
Given the 2 equations
2y - x = 5 → (1)
x² + y² - 25 = 0 → (2)
Rearrange (1) expressing x in terms of y
x = 2y - 5 → (3)
Substitute x = 2y - 5 into (2)
(2y - 5)² + y² - 25 = 0 ← expand parenthesis and simplify
4y² - 20y + 25 + y² - 25 = 0
5y² - 20y = 0 ← factor out 5y from each term
5y(y - 4) = 0
Equate each factor to zero and solve for y
5y = 0 ⇒ y = 0
y - 4 = 0 ⇒ y = 4
Substitute these values into (3) for corresponding values of x
y = 0 : x = 0 - 5 = - 5 ⇒ (- 5, 0)
y = 4 : x = 8 - 5 = 3 ⇒ (3, 4)
Answer:
The answer is A, 64%
Step-by-step explanation:
Answer:
4120 feets
Step-by-step explanation:
Given that:
Starting elevation = 0 feets
Elevation gained on first day = 2150 feets
Total elevation at the end of day 1 = 0 + 2150 = 2150 feets
Elevation gained on second day = 1970 feets
Total elevation at the end of day 2 = 2150 + 1970 = 4120 feets
Elevation at the end of 3 rd day = 0 feets
Hence, elevation lost on day 3 ;
(4120 - 0) = 4120 feets