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stich3 [128]
3 years ago
12

Subtract 5x^2 – 2x – 5 from – 2x^2 - 5x - 7

Mathematics
2 answers:
Paladinen [302]3 years ago
6 0

Answer:

-7x² -3x - 2

Step-by-step explanation:

(-2x²-5x -7) - (5x² - 2x - 5)

removing parentheses

-2x² -5x - 7 -5x² + 2x + 5

collect like terms

-2x² - 5x² -5x + 2x -7 + 5

= -7x² -3x - 2

user100 [1]3 years ago
3 0

Answer:

-7x^{2} -3x-2

Step-by-step explanation:

(-2x^2-5x-7) - (5x^2-2x-5)\\\\-2x^2 - 5x^2  = -7 x^2\\-5x - -2x = -3x\\-7 - -5 = -2 \\Result: -7x^2-3x-2

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Iteru [2.4K]

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Range:-> ((-infinity),infinity)

increasing in (-2.8,1.4)

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Hope it helps...

Regards,

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5 0
3 years ago
Given the equation 4x2 − 8x 20 = 0, what are the values of h and k when the equation is written in vertex form a(x − h)2 k = 0?
Westkost [7]

The vertex form of the given quadratic equation is

4(x-1)^{2} + 16 =0.

According to the given question.

We have a quadratic equation

4x^{2} -8x + 20 = 0

Since, for the standard quadratic form is ax^{2} +bx + c = y, the vertex form of a quadratic equation is y = a(x -h)^{2} + k where (h, k) is the vertex.    

And h and k can be calculated as

h = -b/2a and y = k

So, for the given equation 4x^{2} -8x + 20 =0 the vertex (h, k) is given by

h = -(-8)/2(4) = 8/8 = 1   (X coordinate of vertex)

and,

y =4x^{2} -8x+ 20

substitute x = 1 in the above equation for the value of k

Y = 4(1)(1) - 8(1) + 20

⇒ Y = 4 - 8 + 20

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⇒ Y = 16

so, k = 16          (Y coordinate of vertex)

Now, substitute the value of a, k and h in y = a(x-h)^{2} + k.

⇒  0 =4(x-1)^{2} + 16

Therefore, the vertex form of the given quadratic equation is

4(x-1)^{2} + 16 =0.

Find out more information about vertex form of a quadratic equation here:

brainly.com/question/12223454

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6 0
1 year ago
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Step-by-step explanation:

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Cheers.

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3 years ago
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