Answer:
The correct answer is d.
Step-by-step explanation:
Any point that is co planar with one another and is also equidistant from a given point is a circle. We need it to be co planar, otherwise it would be 3-dimensional and create a sphere. And if they we not all equidistant, they would not make an even circle (it'd be an oval or another shape).
Answer:
50.40% probability that all 4 are different.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Desired outcomes:
4 digits, all different
For the first digit, it can be any of them, so there are 10 possible
For the second digit, it can be any of them other than the first digit. So there are 9 possible.
For the third digit, it can be any of them, other than the first and the second. So there are 8 possible.
By the same logic, 7 possible digits for the fourth. So
Total outcomes:
4 digits, each can be any of them(10 from 0 - 9).
So
Probability:
50.40% probability that all 4 are different.
ik the first answer choice is false
See photo. I hope it helps
Step-by-step explanation:
to find a common denominator, you have to find a number that "works" with every other number.
for example, say you have
2/4 and 8/12
First you need to find the common factor between 4 and 12, so list all your fours
4, 8, 12, 16, 20
Now list all your twelves
12, 24, 36, 48, 60
to find the common factor you look at both your list of numbers and find one that's the same, sometimes it takes a long list of numbers to find the common factor, but you will run into one.
So by looking at our list we see that 4 and 12 share the common factor of 12. but since 8/12 already has a denominator of 12, we are going to leave it alone.
now think about what you would multiply 4 by, to get to 12. The answer is
4 x 3 = 12
to make the numerator correct, you multiply it by the same number you did 4, so since your faction is 2/4 you should do 2 x 3 = 6
now you have your answer,
2/4 and 8/12 turns into
6/12 and 8/12
and that's how you find it, let me know if you have questions :)