Can u go closer I can’t see
Answer:
A=34, G=31
Step-by-step explanation:
G=A-3
2G+A=99
plug in for g 2(A-3)+A=99
distribute 2 A-3+A=99
combine like terms 3A-3=99
solve for a 3A=102 A=34
plug in a solve for g G=34-3 G=31
1 joule = 6,242e+18ev
20 joule = 20 joule *6,242e+18 ev/joule =1,248e+20 ev
1,248e+20 ev / (10 ev / photon) =1,248e+19 photons.
The second one is the best answer in my opinion i'm not sure.
