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podryga [215]
3 years ago
14

A student throws a small rock straight upwards. The rock rises to its highest point and then falls back down. How does the speed

of the rock at 2m on the way down compare with its speed at 2m on the way up?
Physics
1 answer:
Vladimir [108]3 years ago
5 0

Answer:

we assume that it starts with a velocity of 10m/s. At 2m height above ground level, its velocity decreases at 3m above ground level

for its way down the velocity at 3m on its way down is more than its velocity at 2m on its way down.

Explanation:

A student throws a small rock straight upwards. The rock rises to its highest point and then falls back down. How does the speed of the rock at 2m on the way down compare with its speed at 2m on the way up?

It decreases in speed on its way down and increases in speed on its way down.

it decreases in speed on its way up because the the vertical motion is against the earths gravitational pull on an object to the earth's center

.It increases in speed on his way down because its under the influence of gravity

from newton's equation of motion we can check by

using V^2=u^2+2as

we assume that it starts with a velocity of 10m/s. At 2m height above ground level, its velocity decreases at 3m above ground level

for its way down the velocity at 3m on its way down is more than its velocity at 2m on its way down.

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A skier with a mass of 63 kg starts from rest and skis down an icy (frictionless) slope that has a length of 50 m at an angleof
victus00 [196]

Answer:

Explanation:

When the skier reaches the bottom of the slope , height lost by it

h = 50 sin32 m

= 26.5 m

potential energy lost

= mgh

Gain of kinetic energy

= 1/2 mv²

mgh = 1/2 mv²

v = √ 2gh

= √ (2x9.8 x 26.5)

= 22.8 m /s

b )

Let μ be the coefficient of kinetic friction required.

friction force acting

= μmg

work done by friction in displacement of  d (40 m ) on horizontal surface

- μmg x d

This negative work will be equal to positive kinetic energy of the skier on horizontal surface .

=  μmg x d  = (1/2) m v²

μ = v² / (2 gd)

= 519.4 / (2 x 9.8 x 140 )

= .19

8 0
4 years ago
A given mass of air has a volume of 6.00 L at 101 kPa. At constant temperature, the pressure is decreased to 25.0 kPa. Calculate
Sidana [21]

Answer:

24.24L

Explanation:

According to Boyle's law which states that "the volume of a given mass of gas at constant temperature is inversely proportional to its pressure". Mathematically, P = k/V where;

P is the pressure

V is the volume

k is the proportionality constant

PV = k

P1V1 = P2V2

P1 and P2 are initial and final pressure respectively

V1 and V2 are the initial and final volume respectively

Given P1 = 101kPa V1 = 6.0L, P2 = 25kPa V2 = ?

From the formula;

V2 = P1V1/P2

V2 = 101×6/25

V2 = 24.24L

The final volume for the gas is 24.24L

6 0
4 years ago
in vision, the ____ stream controls identification of an object, and the ____ stream controls action toward the object.
prisoha [69]

Answer: In vision, the ventral stream controls identification of an object, and the dorsal stream controls action toward the object.

Explanation: The ventral stream is associated with object recognition and form representation.

Dorsal stream  a pathway that carries visual information from the primary visual cortex to the parietal lobe.

Hope it helps :)

7 0
2 years ago
Which refers to the area on the thermometer marked with the letter A? scale bulb mercury strip number line
expeople1 [14]

Answer:

number line

Explanation: hope this helps lol

8 0
3 years ago
Read 2 more answers
The capacitance of the variable capacitor of a radio can be changed from 100 to 350 pF by turning the dial from 0° to 180°. With
tangare [24]

Answer:

0.7 mJ

Explanation:

<u>Identify the unknown:  </u>

The work required to turn the dial from 180° to 0°  

<u>List the Knowns:  </u>

Capacitance when the dial is set at 180°: C = 350 pF = 350 x 10^-12 F Capacitance when the dial is set at 0°: C = 100 pF = 100 x 10^-12 F  

Voltage of the battery: V = 130 V  

<u>Set Up the Problem:</u>  

<em><u>Energy stored in a capacitor: </u></em>

U_c=1/2*V^2*C

      =1/2*Q^2/C

<em><u>When the dial is set at 180°:</u></em><em>  </em>

U_c=1/2*(130)^2*350*10^-12=10^-4

Q=√2*U_c*C=4*10^-7

<u><em>When the dial is set at 0°:</em></u>  

U_c=1/2*(4*10^-7)^2/100*10^-12

      =8*10^-4 J

<u><em>Solve the Problem:  </em></u>

ΔU_c=7*10^-4 J

        =0.7 mJ

note:

there maybe error in calculation but method is correct

4 0
3 years ago
Read 2 more answers
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