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kap26 [50]
2 years ago
15

Least count of measruing cylinder​

Physics
1 answer:
earnstyle [38]2 years ago
3 0

Answer:

0.1 mm

Explanation:

if the diameter of a cylinder measured by vernier callipers the least count is 0.1 mm or equal to 2cm

Hope This Helped

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A bus starts from rest.if the acceleration is 2m/s square, find
MrMuchimi

Answer:

The velocity after 2 seconds can be found through:

V = u +a*t

Where V is final velocity, u is initial velocity, a is acceleration and t is time.

V = 0 + 2* 2= 4 meters/second

The distance (s) can be found through:

V^2= u^2 +2*a* s

Where V is final velocity, u is initial velocity, a is acceleration.

4^2= 0^2 + 2 *2*s

16= 0 + 4s

s= 4 meters

Distance (s) can also be found through:

s= ut + 1/2 at^2

s= 0+ 1/2 *2*2^2= 1 *2*2

s= 4 meters

Explanation:

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1 year ago
The Coriolis effect
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3 years ago
In which part of the EM spectrum do you see the colors red, orange, yellow, green, blue, indigo, and violet (ROYGBIV);
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Answer:

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Explanation:

hope it helps

7 0
3 years ago
two idential train engines are parked on parallel track. one engine has ten cars attached and the other has no cars attached. ea
nikklg [1K]

Answer:

The second engine with no cars will accelerate more.

Explanation:

Since the engines are identical so they hacve the same mass. The first engine has 10 cars attached which adds more mass to it whereas second engine has no cars attached.

Therefore second engine is lighter in mass than the first one.

<u>We know from the Newton's second law of motion:</u>

F=m.a

\therefore a=\frac{F}{m}

Now, according to question both the engines exert same force for moving.

We see that :

a\propto\frac{1}{m}

So more is the mass, lesser is the acceleration, hence the second engine with no cars will accelerate more.

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3 years ago
Calculate the electric field strength required to just support an oil drop of mass
Ray Of Light [21]

Answer:

E= 3.06 \times 10^{-17} N/C

Explanation:

As we know that the oil drop experiment tells us the balancing the gravitational force by electrostatic force.

So ,

Electrostatic force = Gravitational force

qE=mg

Here , q is charge , E is electric field , m is mass and g is gravity.

so,

E=\frac{mg}{q}

Insert values from question,

E=\frac{10^{-2}kg \times 9.8 m/s^{2}}{3.2 \times 10^{-19}C}

or

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This is the required value of electric field.

3 0
3 years ago
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