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4 years ago

How are metamorphic rocks like igneous rocks? How are they like sedimentary rocks?

1 answer:

6 0

Sedimentary rocks become metamorphic in the rock cycle when they are subjected to heat and pressure from burial. The high temperatures are produced when the Earth's tectonic plates move around, producing heat. And when they collide, they build mountains and metamorphose.

Igneous rocks form as magma cools below ground or lava cools on the surface. Sedimentary rocks are made from the eroded particles of other rocks or from mineral deposits left when water evaporates. Metamorphic rocks form when any existing rock undergoes intense and prolonged exposure to heat and pressure.

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1. In 10 seconds, a car accelerates 4 m/s/s to 60 m/s. How fast was the car going before it accelerated?

ladessa [460]

4m/s is the answer you are looking for

3 0

3 years ago

Jonah finds a rusty nail outside. The nail is an example of _____.

Pani-rosa [81]

I believe the correct answer from the choices listed above is option A. Jonah finds a rusty nail outside. The nail is an example of <span>chemical weathering. Rusting of nail is a result of reaction of iron with water in air. Hope this answers the question. Have a nice day.</span>

3 0

3 years ago

Read 2 more answers

Viewers of Star Trek hear of an antimatter drive on the Starship Enterprise. One possibility for such a futuristic energy

Dominik [7]

a) 0.261 T

b) this field strength is obtainable with today's technology

Explanation:

The force experienced by a charged particle moving perpendicular to a magnetic field is given by

$F=qvB$

where

q is the charge

v is the velocity

B is the strength of the field

This force is perpendicular to the motion of the particle, which therefore moves in a circular path; and so, this force acts as centripetal force, so we can write:

$qvB=m\frac{v^2}{r}$

where

m is the mass of the particle

r is the radius of the circle

In this problem, we have:

$q=1.6\cdot 10^{-19}C$ (magnitude of the charge of antiprotons)

$v=5.00 \cdot 10^7 m/s$ (velocity)

$m=1.67\cdot 10^{-27}kg$ (mass of antiprotons)

r = 2.00 m (radius)

Therefore, we can re-arrange the equation and solve to find B, the magnetic field strength:

$B=\frac{mv}{qr}=\frac{(1.67\cdot 10^{-27})(5.00\cdot 10^7)}{(1.6\cdot 10^{-19})(2.00)}=0.261 T$

The strength of the magnetic field calculated in part A) is

$B=0.261 T$

This is indeed a very strong magnetic field. In fact, by comparison, the Earth's magnetic field has a strength of about

$B_{earth}=5\cdot 10^{-5} T$

However, there are current technologies available that are able to produce such strong fields. For instance, the superconducting magnets in the LHC (Large Hadron Collider) are able to produce magnetic fields of strength up to 8 Tesla (8 T).

Therefore, we can say that this field strength is obtainable with today's technology.

5 0

3 years ago

Calculate the net force on particle qi.

aksik [14]

Answer:

-12.12

Explanation:

i just added them together and it worked.

4 0

2 years ago

The hour and minute hands of a tower clock like Big Ben in London are 2.79 m and 4.44 m long and have masses of 58.2 kg and 90 k

LuckyWell [14K]

Answer: 895.85 x 10^-6 J or 8.96 x 10^-4 J

Explanation:

Angular kinetic energy E in Joules

E = ½Iw^2

W is angular velocity in radians/sec

1 radian/sec = 9.55 rev/min

I is moment of inertia in kgm^2

I = cMR^2

M is mass (kg), R is radius (meters)

c = 1/3 for a rod around its end, R = length

For minute hand

I = (1/3)(90)(4.44)^2 = 0.33 x 90 x 19.7136 = 585.49

w= 1 rev/hour = 1 rev/3600sec = 2pi/ 3600 = pi/1800 rad/s

KE = 1/2(1/3)(90)(4.44)^2(pi/1800)^2 = 0.5 x 0.33 x 90 x 19.7136 x 3.05 x 10^-6

KE = 0.00089 J

For hour hand

I = (1/3)(58.2)(2.79)^2 = 0.33 x 58.2 x 2.79^2 = 149.5

w = 1 rev/12hour = 1 rev/(12x3600sec) = 2pi/ 12x3600 = pi/21600 rad/s

KE = 1/2(1/3)(90)(4.44)^2(pi/21600)^2 = 0.5 x 0.33 x 90 x 19.7136 x 2.12 x 10^-8

KE = 5.85 x 10^-6 J

Therefore total kinetic energy = 895.85 x 10^-6 J

4 0

4 years ago