Answer:
A, 0.59A
Explanation:
The total resistance in the circuit is the resistances in parallel plus that in series.
Total resistance for those in parallel is;
1/(1/4 +1/6 +1/10) = 1/ (15+10+6 /60)
1/(31/60)= 60/31 ohms
Hence total resistance of the circuit is;
60/31 + 2 = (60+62)/31 = 122/31=3.94 ohms
To calculate the current flowing through the 10ohm resistance we need to know the voltage drop by subtracting the voltage drop in the 2ohm resistance from the total voltage drop.
Voltage drop on the 2 ohm resistance is;
Current on the 2 ohm resistor × 2 ohms
V = I ×R ; I - current
R - resistance
Current drop on the 2ohm resistance is;
Total voltage in the circuit/ total resistance in the circuit
12/3.94= 3.05A
Voltage drop on the 2 ohm resistance;
3.05 × 2 = 6.10volts
Hence voltage drop on the parallel resistance would be ;
12-6.10= 5.90V
Now voltage drop in a parallel circuit is the same hence 5.90v is dropped in each of the parallel resistance.
That said, the current drop on the 10 ohm resistor would be;
5.90/10 = 0.59A
Remember V= I× R so that I = V/R
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