What item can be arranged to transform electrical energy to mechanical energy

The thickest and strongest chamber in the human heart is the left ventricle, responsible during systole for pumping oxygenated b

Bess [88]

Answer:

(a). The blood travel during this acceleration is 0.0231 m.

(b). The time for the blood to reach its peak speed is 0.0459 sec.

Explanation:

Given that,

Acceleration = 22.0 m/s²

Speed = 1.01 m/s

(a). We need to calculate the distance

Using equation of motion

$v^2=u^2+2as$

Where, v = final speed

u = initial speed

a = acceleration

s = distance

Put the value into the formula

$(1.01)^2=0+2\times22.0\times s$

$s=\dfrac{(1.01)^2}{2\times22.0}$

$s=0.0231\ m$

(b). We need to calculate the time

Using equation of motion

$v =u+at$

Put the value into the formula

$1.01=0+22t$

$t=\dfrac{1.01}{22}$

$t=0.0459\ sec$

Hence, (a). The blood travel during this acceleration is 0.0231 m.

(b). The time for the blood to reach its peak speed is 0.0459 sec.

4 0

4 years ago

Explain what is meant by “field” and compare the properties of gravitational, electric, and magnetic forces in terms of particle

notsponge [240]

Field in this context refers to a region of the space to which corresponds a value.

There is a gravitational field around the earth, because a mass m placed at any point around the earth will be atracted (gravitational force) by it.

There is an electric field in a point when a charge placed there feels an electric force.

The gravitational field is proportional to the value of the mass of the object that produces it.

The electric field is proportional to the magnitude of the charge of the particle that produces it.

The gravitational field is always attractive. The electric field may be attractive or repulsive.

Both fields are proportional to the inverse of the squared distance.

The magnetic field is created when a charge is in movement,i.e a charge in movement will create a magnetid fiedl around it that will act and create a magnetic force over other charge also in movement.

The magnetic field is proportional to the product of the charge times its velocity and inversely proportional to the squared distance. The force generated my be attractive or repulsive.

6 0

3 years ago

When hoisting a personnel platform which of the following need not be engaged when they occupied platform is in a stationary pos

aivan3 [116]

The answer is <span>Guardrails and protective equipment. </span><span>When hoisting a personnel platform, guardrails and protective equipment need not be engaged when they occupied platform is in a stationary position. </span>

3 0

4 years ago

A 9.00 g bullet is fired horizontally into a 1.20 kg wooden block resting on a horizontal surface. The coefficient of kinetic fr

Ksivusya [100]

a) The initial speed of the bullet is 330.5 m/s

b) The collision is inelastic

c) The impulse is -2.97 kg m/s

Explanation:

a)

The energy lost by the block while sliding (which is equal to the work done by friction) is equal to the kinetic energy of the block after the bullet has been embedded into it, therefore we can write

$KE=W$

$\frac{1}{2}(M+m)v^2=(\mu (M+m)g) d$

where

M = 1.20 kg is the mass of the block

m = 9.00 g = 0.009 kg is the mass of the bullet

v is the combined speed of bullet+block after the collision

$\mu = 0.20$ is the coefficient of friction

$g=9.8 m/s^2$ is the acceleration of gravity

d = 0.310 m is the distance through which the block slides

Solving for v,

$v=\sqrt{2gd}=\sqrt{2(9.8)(0.310)}=2.46 m/s$

This is the final velocity of the block+bullet after the collision.

Now we can apply the law of conservation of momentum: in fact, the total momentum of the system before the collision must be equal to the total momentum after the collision, so we get

$mu+MU = (m+M)v$

where

u is the initial velocity of the bullet

U = 0 is the initial velocity of the block (initially at rest)

v = 2.46 m/s

Solving for u,

$u=\frac{(m+M)v}{m}=\frac{(0.009+1.20)(2.46)}{0.009}=330.5 m/s$

b)

To check whether the collision is elastic or inelastic, we just need to compare the total kinetic energy before and after the collision.

Before the collision, we have:

$K_i = \frac{1}{2}mu^2 = \frac{1}{2}(0.009)(330.5)^2=491.5 J$

While after the collision

$K_f = \frac{1}{2}(m+M)v^2 = \frac{1}{2}(0.009+1.20)(2.46)^2=3.7 J$

We see that the final kinetic energy is less than the initial kinetic energy: therefore, the collision is inelastic, since part of the energy has been converted into other forms of energy (e.g. thermal energy).

c)

The impulse of the block is equal to its change in momentum, so:

$I=\Delta p =p_f - p_i = (m+M)v'-(m+M)v$

where

v' = 0, since the block comes to a stop

v = 2.46 m/s is the velocity of the block just after the collision

Substituting,

$I=0-(0.009+1.20)(2.46)=-2.97 kg m/s$

And the impulse is negative, because its direction is opposite to the direction of motion of the block (this means that the force exerted on the block, which is the force of friction, acts in the direction opposite to the motion of the block).

Learn more about kinetic energy and momentum:

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#LearnwithBrainly

3 0

4 years ago

Samuel is running in a parks nature trail.at first checkpoint he ran 925 m in 10 minutes.at second checkpoint he slowed down and

geniusboy [140]

Answer: