What causes the alternating pattern of night and day? A.

3. A large passenger ship required a force of 1,600,000 N to move 2000 m. How much work is done on the ship?

Dovator [93]

Answer:

3,200,000,000 J

Explanation:

Work is defined as the amount of energy transferred as an object is moved a certain distance with a certain force. Mathematically, we express this with the equation

$W=Fs$

where W is work (measured in joules), F is the force applied (in Newtons), and s is the distance, also called the <em>displacement </em>(in meters).

Here, we have F = 1,600,000 N and s = 2000 m, so our work will be

$W=1.600.000(2.000)=3.200.000.000$ J

7 0

3 years ago

Indicar objetosque puedan ser observados a simple vista, con microscopio, con microscopio electrico y con miscroscopio de transm

AysviL [449]

Answer:

En esta respuesta voy a usar la unidad μm, tal que:

1 μm = 1*10^(-9) m

Objetos que pueden ser observados a simple vista:

Son todos aquellos objetos que podemos observar simplemente con nuestros ojos, con ellos podemos observar desde un edificio (con tamaños de decenas de metros) hasta algunos cabellos, que pueden tener un diámetro de 0.1 mm

Cosas más pequeñas que estás muy difícilmente se pueden ver a simple vista.

Con un microscopio podremos ver cosas del tamaño de una célula, como glóbulos blancos, rojos, algunos microorganismos, etc, los cuales rondan un tamaño de unos 10 μm. Naturalmente, distintos microscopios tendrán distintas amplificaciones (por lo que con algunos podremos ver objetos muy pequeños que con otros no).

Microscopio eléctrico:

Este microscopio usa electrones en lugar de luz para formar imágenes.

Con él podremos observar cosas como las componentes de una célula (membranas, orgánulos grandes, etc), los cuales pueden medir unos pocos nanómetros (por ejemplo, una membrana celular tendrá un tamaño de entre 5 μm y 10 μm)

Microscopio de transmisión.

Tener en cuenta que el microscopio de transmisión es un microscopio eléctrico, el cual lanza un haz de electrones al objeto que se desea observar, de tal forma que algunos de estos electrones rebotan formando así la imagen virtual amplificada que podemos observar.

Con estos aparatos podemos ver orgánulos pequeños (0.5 μm), y lo más pequeño que podemos ver (con los microscopios más potentes) son columnas de átomos (0.1 μm)

6 0

3 years ago

How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro's number of ele

luda_lava [24]

Answer:

W = 1.5 x 10⁶ J = 1.5 MJ

Explanation:

First, we calculate the potential difference between the given 2 points. So, we have:

V₁ = Electric Potential at Initial Position = 6.7 V

V₂ = Electric Potential at Final Position = - 8.9 V

Therefore,

ΔV = Potential Difference = V₂ - V₁ = -8.9 V - 6.7 V = - 15.6 V

Since, we use magnitude in calculation only. Therefore,

ΔV = 15.6 V

Now, we calculate total charge:

Total Charge = q = (No. of Electrons)(Charge on 1 Electron)

where,

No. of Electrons = Avagadro's No. = 6.022 x 10²³

Charge on 1 electron = 1.6 x 10⁻¹⁹ C

Therefore,

q = (6.022 x 10²³)(1.6 x 10⁻¹⁹ C)

q = 96352 C

Now, from the definition of potential difference, we know that it is equal to the worked done on a unit charge moving it between the two points of different potentials:

ΔV = W/q

W = (ΔV )(q)

where,

W = work done = ?

W = (15.6 V)(96352 C)

7 0

3 years ago

Flies could be prey to predator plants, too what plant snacks on this fly?

sertanlavr [38]

Answer:

A Venus Fly trap

Explanation:

4 0

3 years ago

Two asteroids collide and stick together. The first asteroid has mass of 1.50 × 104 kg andis initially moving at 0.77 × 103 m/s.

KengaRu [80]

Answer:

Magnitude 900m/s, direction 12.8° respect to the velocity of the first asteroid.

Explanation:

This is a perfectly inelastic collision, because the two asteroids stick together at the end. That means that the kinetic energy doesn't conserves, but the linear momentum does. But, since the velocities of the asteroids have different directions, we have to break down them in components. For convenience, we will take the direction of the first asteroid as x-axis, and its perpendicular direction (in the plane of the two velocity vectors) as y-axis. So, we have that:

$p_{1ox}+p_{2ox}=p_{fx}\\\\p_{2oy}=p_{fy}$

And, since $p=mv$ , we get:

$m_1v_{1o}+m_2v_{2o}\cos\theta=(m_1+m_2)v_{fx}\\\\m_2v_{2o}\sin\theta=(m_1+m_2)v_{fy}$

Solving for v_fx and v_fy, and calculating their values, we get:

$v_{fx}=\frac{m_1v_{1o}+m_2v_{2o}\cos\theta}{m_1+m_2}\\\\\implies v_{fx}=\frac{(1.50*10^{4}kg)(0.77*10^{3}m/s)+(2.00*10^{4}kg)(1.02*10^{3}m/s)\cos20\°}{1.50*10^{4}kg+2.00*10^{4}kg}=878m/s\\\\\\v_{fy}=\frac{m_2v_{2o}\sin\theta}{m_1+m_2}\\\\\implies v_{fy}=\frac{(2.00*10^{4}kg)(1.02*10^{3}m/s)\sin20\°}{1.50*10^{4}kg+2.00*10^{4}kg}=199m/s$

Now, the final speed can be calculated using the Pythagorean Theorem:

$v_f=\sqrt{v_{fx}^{2}+v_{fy}^{2}} \\\\\implies v_f=\sqrt{(878m/s)^{2}+(199m/s)^{2}}=900m/s$

And the direction $\beta=\arctan \frac{v_{fy}}{v_{fx}}\\ \\\implies \beta=\arctan\frac{199m/s}{878m/s}=12.8\°$ can be obtained using trigonometry:

$\beta=\arctan \frac{v_{fy}}{v_{fx}}\\ \\\implies \beta=\arctan\frac{199m/s}{878m/s}=12.8\°$

That means that the final velocity of the two asteroids has a magnitude of 900m/s and a direction of 12.8° with respect to the velocity of the first asteroid.

7 0

4 years ago