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larisa86 [58]
3 years ago
14

How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro's number of ele

ctrons from an initial point where the electric potential is 6.70 V to a point where the electric potential is -8.90 V? (The potential in each case is measured relative to a common reference point.)
Physics
1 answer:
luda_lava [24]3 years ago
7 0

Answer:

W = 1.5 x 10⁶ J = 1.5 MJ

Explanation:

First, we calculate the potential difference between the given 2 points. So, we have:

V₁ = Electric Potential at Initial Position = 6.7 V

V₂ = Electric Potential at Final Position = - 8.9 V

Therefore,

ΔV = Potential Difference = V₂ - V₁ = -8.9 V - 6.7 V = - 15.6 V

Since, we use magnitude in calculation only. Therefore,

ΔV = 15.6 V

Now, we calculate total charge:

Total Charge = q = (No. of Electrons)(Charge on 1 Electron)

where,

No. of Electrons = Avagadro's No. = 6.022 x 10²³

Charge on 1 electron = 1.6 x 10⁻¹⁹ C

Therefore,

q = (6.022 x 10²³)(1.6 x 10⁻¹⁹ C)

q = 96352 C

Now, from the definition of potential difference, we know that it is equal to the worked done on a unit charge moving it between the two points of different potentials:

ΔV = W/q

W = (ΔV )(q)

where,

W = work done = ?

W = (15.6 V)(96352 C)

<u>W = 1.5 x 10⁶ J = 1.5 MJ</u>

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F = ma
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6 0
3 years ago
A rope is being pulled with a force of 366 N parallel to the horizontal surface right, five men are pulling the same rope parall
lakkis [162]

The amount of force applied by individual man to balance the force at the right is 73.2 N.

<h3>Amount of force applied by individual man</h3>

The amount of force applied by individual man to balance the force at the right is calculated as follows;

F_{right} = F_{left}\\\\F_{left} = F_1 + F_2 + F_3 + F_4 + F_5\\\\F _1 = F_2 = F_3 = F_4 = F_5\\\\F_1 = \frac{F_{right}}{5} = \frac{366}{5} = 73.2 \ N

Thus, the amount of force applied by individual man to balance the force at the right is 73.2 N.

Learn more about forces here: brainly.com/question/12970081

3 0
2 years ago
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 420 gram setting. It
natta225 [31]

Answer:

P-value of the test statistic is 2.499

Explanation:

given data:

size sample is 24

sample mean is 414 gm

standard deviation is 15

Null hypotheis is

H_0: \mu = 420 gm

H_1 \mu< 420

level of significance is 0.01

from test statics

t = \frac{\hat x - \mu}{\frac{s}{\sqrt{n}}}

degree od freedom is  =  n -1

df = 24 -1 = 13

t = \frac{414 - 420}{\frac{15}{\sqrt{24}}}

t = -1.959

from t table critical value of t at 0.1 significane level and 23 degree of freedom  is 2.499

8 0
3 years ago
Please help me!
Eddi Din [679]

Explanation:

Answer is Heat always flows from a Higher place to a lower place.

If my answer is wrong then I'm sorry!

I hope it's helpful!!

6 0
3 years ago
Read 2 more answers
One positve and one negative charhe jave a force of -5. 00 N between them. If the force changed to -170 N , by what factor did t
stepladder [879]

Answer:

The distance is shortenend by factor .1715

Explanation:

5 n  = 1/r^2

sqrt (1/5) = r

170 n  = 1 / ( x sqrt(1/5))^2

(xsqrt 1/5)^2 = 1/170

x sqrt 1/5  = .076696

x = .1715    

5 0
2 years ago
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