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larisa86 [58]
3 years ago
14

How much work is done (by a battery, generator, or some other source of potential difference) in moving Avogadro's number of ele

ctrons from an initial point where the electric potential is 6.70 V to a point where the electric potential is -8.90 V? (The potential in each case is measured relative to a common reference point.)
Physics
1 answer:
luda_lava [24]3 years ago
7 0

Answer:

W = 1.5 x 10⁶ J = 1.5 MJ

Explanation:

First, we calculate the potential difference between the given 2 points. So, we have:

V₁ = Electric Potential at Initial Position = 6.7 V

V₂ = Electric Potential at Final Position = - 8.9 V

Therefore,

ΔV = Potential Difference = V₂ - V₁ = -8.9 V - 6.7 V = - 15.6 V

Since, we use magnitude in calculation only. Therefore,

ΔV = 15.6 V

Now, we calculate total charge:

Total Charge = q = (No. of Electrons)(Charge on 1 Electron)

where,

No. of Electrons = Avagadro's No. = 6.022 x 10²³

Charge on 1 electron = 1.6 x 10⁻¹⁹ C

Therefore,

q = (6.022 x 10²³)(1.6 x 10⁻¹⁹ C)

q = 96352 C

Now, from the definition of potential difference, we know that it is equal to the worked done on a unit charge moving it between the two points of different potentials:

ΔV = W/q

W = (ΔV )(q)

where,

W = work done = ?

W = (15.6 V)(96352 C)

<u>W = 1.5 x 10⁶ J = 1.5 MJ</u>

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The answer to this question can be defined as follows:

Explanation:

Therefore the 4th harmonicas its node is right and over the pickup so, can not be captured from 16.25, which is 1:4 out of 65. Normally, it's only conceptual for the certain harmonic, this will be low, would still be heard by the catcher.

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3 years ago
When a wave is absorbed by a medium, its energy is transferred to the medium. The energy is most often transformed into thermal
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Answer:

TEMPERATURE

Explanation:

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4 0
3 years ago
A horizontal force of 100 N is used to pull a crate, which weighs 500 N, at constant velocity across a horizontal floor. What is
Ilya [14]

Answer:

0.2

Explanation:

Horizontal force=100N

Weight of crate=500 N

We have to find the coefficient of kinetic friction.

Normal ,N=Weight=500N

Horizontal force,F_x=\mu_kN

Where F_x=Horizontal force

N=Normal force

\mu_k=Coefficient of kinetic friction

Substitute the values in the formula

100=\mu_k(500)

\mu_k=\frac{100}{500}=0.2

Hence, the coefficient of kinetic friction =0.2

8 0
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The y-position of a damped oscillator as a function of time is shown in the figure.
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The length of time that an oscillator is allowed to oscillate, as well as its damping coefficient.

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<h3>What is the period of the oscillator, and what factors influence the amount of damping that it has?</h3>

In most situations, the equation may be expressed numerically as

When we look at the data and see that there are cycles between the timestamps t= 0s and t= 4s, we may conclude that it finishes three cycles once every four seconds. As a result, the length of time that is going to be necessary to finish one cycle of damping will be

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In most situations, the equation for amplitude may be expressed analytically as

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Therefore

3=5e^{-12b}

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In conclusion, damping refers to an influence that either operates from inside an oscillatory system or acts on it and has the consequence of reducing or halting the system from oscillating. This impact might occur from either side of the system. In physical systems, damping is produced by processes that cause the energy that is stored in an oscillation to be lost. These processes are called dissipative. The collective name for these processes is "damping agents." The damping coefficient may thus be written as

b = 0.0426 s^-1

Learn more about the damping coefficient by reading up on it.

brainly.com/question/15723320

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