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belka [17]
3 years ago
12

Playing soccer on a beach will require more effort because the sand causes a great deal of _______ to the ball.

Physics
2 answers:
34kurt3 years ago
5 0

Answer:

I believe the answer to be B

Explanation:

If you were playing on grass, the ball would be able to roll around much easier rather than it to be on sand. If it's wrong I am so sorry

Gre4nikov [31]3 years ago
5 0
The answer of this question is b
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A 4,000 kg boat floats with one-third of its volume submerged. if two more people get into the boat, each of whom weighs 690 n,
AveGali [126]

 

The weightiness of the added water displaced is equivalent to the joined weight of the two extra people who come to be into the boat:


<span>m water g                   = 2 x 690 N</span>

<span>                                   = 1,380 N</span>

<span>
</span>

The mass of the water displace is then


<span>m water g                   = 1,380 N</span>

<span>                                   = 1,380 N / 9.8 m/s^2</span>

<span>                                   = 141 kg</span>

<span>
</span>

Compute the calculation for density for the volume of water displace and practice this outcome for the mass of the water displace to get the answer:


<span>p water                      = mass of water / volume of water</span>

<span>
</span>

<span>volume of water        = mass of water / p water</span>

<span>                                  = 141 kg / 1000 kg /m^3 eliminate kilogram</span>

<span>                                  = 0.14 m^3 the additional volume of water that is displaced</span>

4 0
3 years ago
What is stored energy?
Yuri [45]
Depends on the situation. It could be something like potential energy of a compressed or stretched spring.
8 0
4 years ago
Under very dim levels of illumination foveas react to increase the sensitivity of the optic nerve. rods are more light-sensitive
Alex777 [14]

Answer:

rods are more light sensitive than cones.

Explanation:

There are two types of photo receptors in retina of our eyes. 1 Rods and 2 Cones. Rods are about 120 million and they are more sensitive then the cones. But the rods are not sensitive to color. Cones help us in seeing the color and there are about 6 to 7 million cones that provide color sensitivity to our eyes. That is why in the dark or where their are dim levels of illumination rods provide us scotopic vision. Because rods are more light sensitive then the cones.

7 0
4 years ago
Read 2 more answers
The change in the internal energy of a system that releases 2,500 j of heat and that does 7,655 j of work on the surroundings is
g100num [7]

We are given that the system “releases” heat of 2,500 J, and that it “does work on the surroundings” by 7,655 J.

The highlighted words releases and does work on the surroundings all refers to that it is the system itself which expends energy to do those things. Therefore the action of releasing heat and doing work has both magnitudes of negative value. Therefore:

heat released = - 2, 500 J

work done = - 7, 655 J

Which means that the total internal energy change of the system is:

change in internal energy = heat released + work

<span>change in internal energy = - 2, 500 J +  - 7, 655 J</span>

<span>change in internal energy = -10,155 J</span>

3 0
4 years ago
The atmosphere of Jupiter is essentially made up of hydrogen, H2. For H2, the specific gas constant is 4157 J/(kg K). The accele
Alenkinab [10]

Answer:

h=17357.9m

Explanation:

The atmospheric pressure is just related to the weight of an arbitrary column of gas in the atmosphere above a given area. So, if you are higher in the atmosphere less gass will be over you, which means you are bearing less gas and the pressure is less.

To calculate this, you need to use the barometric formula:

P=P_0e^{-\frac{Mg}{RT}h}

Where R is the gas constant, M the molar mass of the gas, g the acceleration of gravity, T the temperature and h the height.

Furthermore, the specific gas constant is defined by:

R_{H_2}=\frac{R}{M}

Therefore yo can write the barometric formula as:

P=P_0e^{-\frac{g}{R_{H_2}T}h}

at the surface of the planet (h =0) the pressure is P_0[\tex]. The pressure at the height requested is half of that:[tex]P=\frac{P_0}{2}

applying to the previuos equation:

\frac{P_0}{2} =P_0e^{-\frac{g}{R_{H_2}T}h}

solving for h:

h=17357.9m

3 0
4 years ago
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