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Ad libitum [116K]
3 years ago
14

HELP. A river flows South with a speed of 8m/s. From the shore, you see a boat moving South with a speed of 10 m/s. From their f

rame of reference, how fast are the rowers moving?
Physics
1 answer:
riadik2000 [5.3K]3 years ago
3 0

Answer:

18 m/s

Explanation:

Given that,

Speed of river is 8 m/s due South

From the shore, you see a boat moving South with a speed of 10 m/s. Both boat and river are moving in same direction. The resultant velocity will add up.

v = 10 m/s + 8 m/s

v = 18 m/s

Hence, the rowers are moving with a speed of 18 m/s.

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Raindrops hitting the side windows of a car in motion often leave diagonal streaks even if there is no wind. Why? Is the explana
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Answer:

because of the raindrop velocity relative of the car has a vertical and horizontal component  

Explanation:

  1. The car moves in a <em>horizontal direction </em>relative to the ground. The raindrops fall in the <em>vertical direction</em> relative to the ground.
  2. Their velocity relative to the moving car has  both vertical and horizontal components and this is the reason for the diagonal streaks on the side window.
  3. The diagonal streaks on the windshield  arise from a different reason.
  4. The drops  are pushed  off to  one side  of the  windshield  because  of air resistance.

6 0
3 years ago
Daniel has a sample of pure copper. Its mass is 89.6 grams (g), and its volume is 10 cubic centimeters (cm3). What’s the density
adell [148]
The correct answer is 8.96gl/cm^3*
5 0
3 years ago
You are trying to decide between two new stereo amplifiers. One is rated at 130 W per channel and the other is rated at 200 W pe
NARA [144]

Answer:

The sound level will be 1.870 dB louder.

Explanation:

Given that,

Power = 130 W

Power = 200 W

We need to calculate the sound level

Using formula of sound level

I_{dB}=10\log(\dfrac{I}{I_{0}})

For one amplifier,

I_{1}=10\log(\dfrac{130}{I_{0}})...(I)

For other amplifier,

I_{2}=10\log(\dfrac{200}{I_{0}})...(II)

For difference in dB levels

I_{2}-I_{1}=10\log(\dfrac{200}{I_{0}})-10\log(\dfrac{130}{I_{0}})

I_{2}-I_{1}=10\log(\dfrac{200}{I_{0}}\times\dfrac{I_{0}}{130})

I_{2}-I_{1}=10\log(\dfrac{200}{130})

I_{2}-I_{1}=1.870\ dB

Hence, The sound level will be 1.870 dB louder.

7 0
3 years ago
Which statement is valid.
Serhud [2]

Answer:

as an object gains speed it gains kinetic energy

Explanation:

i am mixed with the very first one i dont really know if its right so if its wrong my bad

3 0
3 years ago
Which of the following plays a major role in creating deep ocean currents
Alchen [17]
C or b is the correct answer
3 0
3 years ago
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