What is the force of an object with a mass of 65 kg and an an unknown acceleration?

Help me asap its due today

Margaret [11]

Answer:

$3.54* 10^{22}$ N

Explanation:

Using the formula you gave:

$F_g = \frac{6.67*10^{-11}*2.0*10^{30}*5.97^{24} }{(1.5*10^{11})^2 }$

3 0

2 years ago

Three crates with various contents are pulled by a force Fpull=3615 N across a horizontal, frictionless roller‑conveyor system.

SIZIF [17.4K]

The question is incomplete. Here is the complete question.

Three crtaes with various contents are pulled by a force Fpull=3615N across a horizontal, frictionless roller-conveyor system.The group pf boxes accelerates at 1.516m/s2 to the right. Between each adjacent pair of boxes is a force meter that measures the magnitude of the tension in the connecting rope. Between the box of mass m1 and the box of mass m2, the force meter reads F12=1387N. Between the box of mass m2 and box of mass m3, the force meter reads F23=2304N. Assume that the ropes and force meters are massless.

(a) What is the total mass of the three boxes?

(b) What is the mass of each box?

Answer: (a) Total mass = 2384.5kg;

(b) m1 = 915kg;

m2 = 605kg;

m3 = 864.5kg;

Explanation: The image of the boxes is described in the picture below.

(a) The system is moving at a constant acceleration and with a force Fpull. Using Newton's 2nd Law:

$F_{pull}=m_{T}.a$

$m_{T}=\frac{F_{pull}}{a}$

$m_{T}=\frac{3615}{1.516}$

$m_{T}=2384.5$

Total mass of the system of boxes is 2384.5kg.

(b) For each mass, analyse each box and make them each a free-body diagram.

For $m_{1}$ :

The only force acting On the $m_{1}$ box is force of tension between 1 and 2 and as all the system is moving at a same acceleration.

$m_{1} = \frac{F_{12}}{a}$

$m_{1} = \frac{1387}{1.516}$

$m_{1}$ = 915kg

For $m_{2}$ :

There are two forces acting on $m_{2}$ : tension caused by box 1 and tension caused by box 3. Positive referential is to the right (because it's the movement's direction), so force caused by 1 is opposing force caused by 3:

$m_{2} = \frac{F_{23}-F_{12}}{a}$

$m_{2} = \frac{2304-1387}{1.516}$

$m_{2}$ = 605kg

For $m_{3}$ :

$m_{3} = m_{T} - (m_{1}+m_{2})$

$m_{3} = 2384.5-1520.0$

$m_{3}$ = 864.5kg

8 0

2 years ago

For which question could a testable hypothesis be developed?

adell [148]

Does wood float in water

8 0

2 years ago

Read 2 more answers

Squids propel themselves by expelling water. They do this by keeping water in a cavity and then suddenly contracting the cavity

Musya8 [376]

Answer:

v_squid = - 2,286 m / s

Explanation:

This exercise can be solved using conservation of the moment, the system is made up of the squid plus the water inside, therefore the force to expel the water is an internal force and the moment is conserved.

Initial moment. Before expelling the water

p₀ = 0

the squid is at rest

Final moment. After expelling the water

$p_{f}$ = M V_squid + m v_water

p₀ = p_{f}

0 = M V_squid + m v_water

c_squid = -m v_water / M

The mass of the squid without water is

M = 9 -2 = 7 kg

let's calculate

v_squid = 2 8/7

v_squid = - 2,286 m / s

The negative sign indicates that the squid is moving in the opposite direction of the water

8 0

3 years ago

HELP

astraxan [27]

Answer:

Ultraviolet light has shorter wavelengths than infrared light. The frequency of ultraviolet light is greater than that of infrared light. Ultraviolet light is higher in energy than infrared light.

7 0

2 years ago