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Igoryamba
3 years ago
12

20. Consider two Stars A and B with temperatures Ta and TB and radii Ra and RB respectively. If TA

Physics
1 answer:
Rus_ich [418]3 years ago
4 0

Answer:

L_A = 9 L_B

Explanation:

The formula that relates the luminosity of a star (L) to its radius (R) and the temperature (T) is

L=\frac{R^2}{T^4}

For star B, we can write:

L_B=\frac{R_B^2}{T_B^4}

For star A, we have

T_A = 2 T_B\\R_A = 12 R_B

So the luminosity of star A is

L_A=\frac{R_A^2}{T_A^4}=\frac{(12 R_B)^2}{(2 T_B)^4}=\frac{144 R_B^2}{16 T_B^4}=9\frac{R_B^2}{T_B^4}=9 L_B

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An oil gusher shoots crude oil 25.0 m into the air through a pipe with a 0.100-m diameter. Neglecting air resistance but not the
Mariana [72]

Answer:3764.282 KPa

Explanation:

Given gusher shoots oil at h=25 m

i.e. the velocity of jet is

v=\sqrt{2gh}[/tex]

v=22.147 m/s

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5 0
3 years ago
A jogger runs 20 mi West and then 6.0 mi North. Find the magnitude and direction of the resultant displacement.
Black_prince [1.1K]

Answer:

The magnitude of the resultant displacement is 21 mi and its direction is 16.7° north of west

Explanation:

Hi there!

Please see the figure for a better understanding of the problem. The total displacement vector will be the sum of both displacements:

The vector for the first displacement is:

First displacement = (20 mi, 0)

The second displacement:

Second displacement = (0, 6.0 mi)

The resultant displacement will be:

R = (20 mi, 0) + (0, 6.0 mi) = (20 mi + 0, 0 + 6.0 mi) = (20 mi, 6.0 mi)

The magnitude of this vector will be:

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The magnitude of the vector displacement is 21 mi.

To find the direction of the vector R, we have to apply trigonometry:

In a right triangle the following trigonometric rule applies:

cos θ = adjacent side to the angle/ hypotenuse

In this case:

cos θ = 20 mi / magnitude of R

θ = 16.7°

The direction of the vector is 16.7° north of west.

4 0
3 years ago
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