Answer:
19 N
Explanation:
From the question given above, the following data were obtained:
Pressure (P) = 1.9 kPa
Length (L) = 10 cm
Force (F) =?
Next, we shall convert 1.9 KPa to N/m². This can be obtained as follow:
1 KPa = 1000 N/m²
Therefore,
1.9 KPa = 1.9 KPa × 1000 N/m² / 1 KPa
1.9 KPa = 1900 N/m²
Thus, 1.9 KPa is equivalent to 1900 N/m².
Next, we shall convert 10 cm to m. This can be obtained as follow:
100 cm = 1 m
Therefore,
10 cm = 10 cm × 1 m / 100 cm
10 cm = 0.1 m
Thus, 10 cm is equivalent to 0.1 m
Next, we shall determine the area of the square. This can be obtained as follow:
Length (L) = 0.1 m
Area of square (A) =?
A = L²
A = 0.1²
A = 0.01 m²
Thus, the area of the square is 0.01 m².
Finally, we shall determine the force that must be exerted on the sensor in order for it to turn red. This can be obtained as follow:
Pressure (P) = 1900 N/m²
Area (A) = 0.01 m²
Force (F) =?
P = F/A
1900 = F / 0.01
Cross multiply
F = 1900 × 0.01
F = 19 N
Therefore, a force of 19 N must be exerted on the sensor in order for it to turn red.
Answer:
The first law, also called the law of inertia, was pioneered by Galileo. This was quite a conceptual leap because it was not possible in Galileo's time to observe a moving object without at least some frictional forces dragging against the motion. In fact, for over a thousand years before Galileo, educated individuals believed Aristotle's formulation that, wherever there is motion, there is an external force producing that motion.
The second law, $ f(t)=m\,a(t)$ , actually implies the first law, since when $ f(t)=0$ (no applied force), the acceleration $ a(t)$ is zero, implying a constant velocity $ v(t)$ . (The velocity is simply the integral with respect to time of $ a(t)={\dot v}(t)$ .)
Newton's third law implies conservation of momentum [138]. It can also be seen as following from the second law: When one object ``pushes'' a second object at some (massless) point of contact using an applied force, there must be an equal and opposite force from the second object that cancels the applied force. Otherwise, there would be a nonzero net force on a massless point which, by the second law, would accelerate the point of contact by an infinite amount.
Explanation:
Answer: Current in a wire
We can use the same right-hand rule as we did for the moving charges—pointer finger in the direction the current is flowing, middle finger in the direction of the magnetic field, and thumb in the direction the wire is pushed.
Explanation:
Answer:
The number of turns in secondary coil is 4000
Explanation:
Given:
Current in primary coil
A
Current in secondary coil
A
Number of turns in primary coil ![N_{P} = 200](https://tex.z-dn.net/?f=N_%7BP%7D%20%3D%20200)
In case of transformer the relation between current and number of turns is given by,
![\frac{N_{S} }{N_{P} } = \frac{I_{P} }{I_{S} }](https://tex.z-dn.net/?f=%5Cfrac%7BN_%7BS%7D%20%7D%7BN_%7BP%7D%20%20%7D%20%3D%20%5Cfrac%7BI_%7BP%7D%20%7D%7BI_%7BS%7D%20%7D)
For finding number of turns in secondary coil,
![N_{S} = \frac{I_{P} }{I_{S} } N_{P}](https://tex.z-dn.net/?f=N_%7BS%7D%20%3D%20%5Cfrac%7BI_%7BP%7D%20%7D%7BI_%7BS%7D%20%7D%20%20N_%7BP%7D)
![N_{S} = \frac{500}{25} \times 200](https://tex.z-dn.net/?f=N_%7BS%7D%20%3D%20%5Cfrac%7B500%7D%7B25%7D%20%5Ctimes%20200)
![N_{S} = 4000](https://tex.z-dn.net/?f=N_%7BS%7D%20%3D%204000)
Therefore, the number of turns in secondary coil is 4000